int[] ar1 = {1,2,3};
int[] ar2 = {1,2,3};
Output:
输出:
{2,3,4,3,4,5,4,5,6}
I tried something like this:
我试过这样的方法:
IntStream.range(0,ar1.length).map(x -> IntStream.range(0,ar2.length).map(y -> ar1[y]+ar2[x]));
but this does not work:
但这行不通:
Type mismatch: cannot convert from
IntStream
toint
.类型不匹配:不能从IntStream转换为int。
How can I sum every value of ar1
with every value of ar2
in Java 8 using streams?
我如何使用流来对Java 8中的ar2的每个值求和?
3 个解决方案
#1
14
You should use flatMap
, since map
of IntStream
is expected to map each int
element of the original IntStream
to an int
, not to an IntStream
.
您应该使用flatMap,因为预期IntStream的映射会将原始IntStream的每个int元素映射到int,而不是IntStream。
System.out.println(Arrays.toString (
IntStream.range(0,ar1.length)
.flatMap(x -> IntStream.range(0,ar2.length).map(y -> ar1[x]+ar2[y]))
.toArray ()));
Output:
输出:
[2, 3, 4, 3, 4, 5, 4, 5, 6]
As an alternative to creating an IntStream
of the indices of the array, you can create an IntStream
of the elements of the array:
作为创建数组索引的IntStream的备选方案,您可以创建数组元素的IntStream:
System.out.println(Arrays.toString (
Arrays.stream(ar1)
.flatMap(x -> Arrays.stream(ar2).map(y -> x + y))
.toArray ()));
#2
8
For each i
th element, you can create a IntStream
of sums i + j
of this element and a j
th element of another array:
对于每个第i个元素,您可以创建该元素的i + j和另一个数组的第j个元素的i + j的IntStream:
IntStream.of(ar1).flatMap(i -> IntStream.of(ar2).map(j -> i + j)).toArray();
I would not recommend using streams of indexes (IntStream.range(0,ar1.length)
) where they can be replaced with streams of values themselves (IntStream.of(ar1)
).
我不建议使用索引流(IntStream.range(0,ar1.length)),在那里可以用价值流替换它们(IntStream.of(ar1))。
#3
6
Beside that of the IntStream#flatMap, you can use the Arrays#stream(int[]) to create an IntStream
. for example:
在IntStream#flatMap的旁边,您可以使用数组#stream(int[])创建一个IntStream。例如:
int[] sum = Arrays.stream(ar1)
.flatMap(left -> Arrays.stream(ar2).map(right -> left + right))
.toArray();
System.out.println(Arrays.toString(sum));
// ^--- [2, 3, 4, 3, 4, 5, 4, 5, 6]
#1
14
You should use flatMap
, since map
of IntStream
is expected to map each int
element of the original IntStream
to an int
, not to an IntStream
.
您应该使用flatMap,因为预期IntStream的映射会将原始IntStream的每个int元素映射到int,而不是IntStream。
System.out.println(Arrays.toString (
IntStream.range(0,ar1.length)
.flatMap(x -> IntStream.range(0,ar2.length).map(y -> ar1[x]+ar2[y]))
.toArray ()));
Output:
输出:
[2, 3, 4, 3, 4, 5, 4, 5, 6]
As an alternative to creating an IntStream
of the indices of the array, you can create an IntStream
of the elements of the array:
作为创建数组索引的IntStream的备选方案,您可以创建数组元素的IntStream:
System.out.println(Arrays.toString (
Arrays.stream(ar1)
.flatMap(x -> Arrays.stream(ar2).map(y -> x + y))
.toArray ()));
#2
8
For each i
th element, you can create a IntStream
of sums i + j
of this element and a j
th element of another array:
对于每个第i个元素,您可以创建该元素的i + j和另一个数组的第j个元素的i + j的IntStream:
IntStream.of(ar1).flatMap(i -> IntStream.of(ar2).map(j -> i + j)).toArray();
I would not recommend using streams of indexes (IntStream.range(0,ar1.length)
) where they can be replaced with streams of values themselves (IntStream.of(ar1)
).
我不建议使用索引流(IntStream.range(0,ar1.length)),在那里可以用价值流替换它们(IntStream.of(ar1))。
#3
6
Beside that of the IntStream#flatMap, you can use the Arrays#stream(int[]) to create an IntStream
. for example:
在IntStream#flatMap的旁边,您可以使用数组#stream(int[])创建一个IntStream。例如:
int[] sum = Arrays.stream(ar1)
.flatMap(left -> Arrays.stream(ar2).map(right -> left + right))
.toArray();
System.out.println(Arrays.toString(sum));
// ^--- [2, 3, 4, 3, 4, 5, 4, 5, 6]