题目大意:给你两个集合,判断两个集合的关系(不相交、相等、真子集和其他)。简单判断就可以了,不过STL的set没有交集、并集等操作有点让人觉得不方便...
#include <cstdio>
#include <iostream>
#include <set>
using namespace std; set<int> intersection(const set<int> &a, const set<int> &b)
{
set<int>::iterator itA = a.begin(), itB = b.begin();
set<int> c;
while (itA != a.end() && itB != b.end())
{
if (*itA == *itB)
{
c.insert(*itA);
itA++;
itB++;
}
else if (*itA < *itB) itA++;
else if (*itA > *itB) itB++;
}
return c;
} int main()
{
#ifdef LOCAL
freopen("in", "r", stdin);
#endif
int x;
while (scanf("%d", &x) != EOF)
{
set<int> A, B, C;
A.insert(x);
C.insert(x);
while (getchar() != '\n')
{
scanf("%d", &x);
A.insert(x);
C.insert(x);
}
scanf("%d", &x);
B.insert(x);
C.insert(x);
while (getchar() != '\n')
{
scanf("%d", &x);
B.insert(x);
C.insert(x);
}
if (A.size() + B.size() == C.size()) printf("A and B are disjoint\n");
else if (A == B) printf("A equals B\n");
else
{
set<int> s = intersection(A, B);
if (A == s) printf("A is a proper subset of B\n");
else if (B == s) printf("B is a proper subset of A\n");
else printf("I'm confused!\n");
}
}
return ;
}
@2013-11-10 11:50:07
前两天看C++ Primer的时候,看到标准库里有set_union(), set_intersection(), set_difference() 和 set_symmetirc_difference()函数,就重写了一下,提交后和上面那个代码时间一样,不过省了不少功夫哈,对c++还是不熟悉啊,还要多学习。
#include <cstdio>
#include <iostream>
#include <set>
#include <algorithm>
using namespace std; int main()
{
#ifdef LOCAL
freopen("in", "r", stdin);
#endif
int x;
while (scanf("%d", &x) != EOF)
{
set<int> A, B, C;
A.insert(x);
C.insert(x);
while (getchar() != '\n')
{
scanf("%d", &x);
A.insert(x);
C.insert(x);
}
scanf("%d", &x);
B.insert(x);
C.insert(x);
while (getchar() != '\n')
{
scanf("%d", &x);
B.insert(x);
C.insert(x);
}
if (A.size() + B.size() == C.size()) printf("A and B are disjoint\n");
else if (A == B) printf("A equals B\n");
else
{
set<int> s;
set_intersection(A.begin(), A.end(), B.begin(), B.end(), inserter(s, s.begin()));
if (A == s) printf("A is a proper subset of B\n");
else if (B == s) printf("B is a proper subset of A\n");
else printf("I'm confused!\n");
}
}
return ;
}