Given a string containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are all valid but "(]"
and "([)]"
are not.
这题虽然简单但是我也没有一次就AC,问题在于取top和pop的时候忘了做异常判断,切记切记。
此外找conterpart也许是个比较头疼的问题,但是用hashmap就方便多了
map<char, char> conterpart; bool isValid(string s) {
conterpart['('] = ')';
conterpart['['] = ']';
conterpart['{'] = '}'; if (s.empty()) return true;
stack<char> st;
for (int i = ; i < s.size(); i++) {
char c = s.at(i);
if (c == '(' || c == '[' || c == '{') {
st.push(c);
}
else if (c == ')' || c == ']' || c == '}'){
if (st.empty()) return false;
if ( conterpart[st.top()] != c) {
return false;
}
else {
st.pop();
}
}
} if (st.empty()) {
return true;
}
return false;
}