Excel can sort records according to any column. Now you are supposed to imitate this function.
Input Specification:
Each input file contains one test case. For each case, the first line contains two integers N (≤) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).
Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.
Sample Input 1:
3 1
000007 James 85
000010 Amy 90
000001 Zoe 60
Sample Output 1:
000001 Zoe 60
000007 James 85
000010 Amy 90
Sample Input 2:
4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98
Sample Output 2:
000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60
Sample Input 3:
4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90
Sample Output 3:
000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90
自定义结构体排序#include <iostream>
#include <algorithm>
#include <string>
#include <cstring>
using namespace std;
struct node
{
string str1,str2;
int str3;
}a[];
int cmp1(node x,node y)
{
return x.str1<y.str1;
}
int cmp2(node x,node y)
{
if(x.str2==y.str2) return x.str1<y.str1;
return x.str2<y.str2;
}
int cmp3(node x,node y)
{
if(x.str3==y.str3) return x.str1<y.str1;
return x.str3<y.str3;
}
int main()
{
int n,m;
while(cin>>n>>m){
for(int i=;i<n;i++){
cin>>a[i].str1>>a[i].str2>>a[i].str3;
}
if(m==){
sort(a,a+n,cmp1);
}else if(m==){
sort(a,a+n,cmp2);
}else if(m==){
sort(a,a+n,cmp3);
}
for(int i=;i<n;i++){
cout<<a[i].str1<<" "<<a[i].str2<<" "<<a[i].str3<<endl;
}
}
return ;
}