字节跳动的一道python面试题

时间:2025-03-17 11:06:43
#!/usr/bin/python
#coding=utf-8
#好好学习,天天向上
lst = ['hongkong','xiantyk','chinat','guangdong','z']
lst2 = []
lst3 = []
lst4 = []
def get_num():
for i in range(len(lst)):
for j in range(i+1,len(lst)):
lst2 = list(lst[i])
lst3 = list(lst[j])
if len(set(lst2+lst3)) == len(lst2+lst3):
num = len(lst2)*len(lst3)
lst4.append(num)
if len(lst4) == 0:
return 0
else:
return max(lst4) if __name__ == '__main__':
print(get_num())

字节跳动的一道python面试题