Reverse a singly linked list.
Example:
Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL
Follow up:
A linked list can be reversed either iteratively or recursively. Could you implement both?
很基本的一道换顺序的题目,先建一个pre 指针,设为None,然后将head.next 存到temp node中,然后将head.next 指针指向pre,接着再将pre和head都依次后移一位。
Code:
1) Basic, using temp node
class ListNode:
def __init__(self, x):
self.val = x
self.next = None class Solution:
def reverseList(self, head):
pre = None
while head:
temp = head.next
head.next = pre
pre = head
head = temp
return pre
2) 利用python可以多重赋值
class Solution:
def reverseList(self, head):
pre = None
while head:
head.next, pre, head = pre, head, head.next
return pre