MySQL：列包含单词列表中的单词

I have a list of words. Lets say they are 'Apple', 'Orange', and 'Pear'. I have rows in the database like this:

我有一个单词列表。让我们说它们是'Apple'，'Orange'和'Pear'。我在数据库中有这样的行：

------------------------------------------------
|author_id   |  content                        |
------------------------------------------------
| 54         | I ate an apple for breakfast.   |
| 63         | Going to the store.             |
| 12         | Should I wear the orange shirt? |
------------------------------------------------

I'm looking for a query on an InnoDB table that will return the 1st and 3rd row, because the content column contains one or more words from my list. I know I could query the table once for each word in my list, and use LIKE and the % wildcard character, but I'm wondering if there is a single query method for such a thing?

我正在寻找一个返回第1行和第3行的InnoDB表的查询，因为内容列包含我列表中的一个或多个单词。我知道我可以为列表中的每个单词查询一次表，并使用LIKE和％通配符，但我想知道是否有一个单一的查询方法用于这样的事情？

2 个解决方案

#1

EDIT:

编辑：

Something like this:

像这样的东西：

SELECT * FROM yourtable WHERE content LIKE '%apple%' OR content LIKE '%orange%'

You can loop your words to create WHERE clause conditions.

您可以循环您的单词以创建WHERE子句条件。

For Example:

例如：

$words = array( 'apple', 'orange' );
$whereClause = '';
foreach( $words as $word) {
   $whereClause .= ' content LIKE "%' . $word . '%" OR';
}

// Remove last 'OR'
$whereClause = substr($whereClause, 0, -2);

$sql = 'SELECT * FROM yourtable WHERE' . $whereClause;

echo $sql;

Output:

输出：

SELECT * FROM yourtable WHERE content LIKE "%apple%" OR content LIKE "%orange%"

#2

MySQL (I believe the 5.0 version) added the ability to use regular expressions in your SQL.

MySQL（我相信5.0版本）增加了在SQL中使用正则表达式的能力。

Check out: http://www.brainbell.com/tutorials/MySQL/Using_MySQL_Regular_Expressions.htm

查看：http：//www.brainbell.com/tutorials/MySQL/Using_MySQL_Regular_Expressions.htm

SELECT author_id, content
FROM AuthorTableName
WHERE content REGEXP 'Apple|Orange|Pear'
ORDER BY author_id;

#1