I've been smashing my head against a brick wall with this one, i've tried loads of the solutions on * but can't find one that works!
我一直用这个方法把我的头撞在砖墙上,我试过很多*上的解决方案,但是找不到一个有效的!
Basically when I POST my AJAX the PHP returns JSON but the AJAX shows Undefined instead of the value:
基本上,当我发布AJAX时PHP返回JSON但AJAX显示的是未定义的而不是值:
JS:
JS:
/* attach a submit handler to the form */
$("#group").submit(function(event) {
/* stop form from submitting normally */
event.preventDefault();
/*clear result div*/
$("#result").html('');
/* get some values from elements on the page: */
var val = $(this).serialize();
/* Send the data using post and put the results in a div */
$.ajax({
url: "inc/group.ajax.php",
type: "post",
data: val,
datatype: 'json',
success: function(data){
$('#result').html(data.status +':' + data.message);
$("#result").addClass('msg_notice');
$("#result").fadeIn(1500);
},
error:function(){
$("#result").html('There was an error updating the settings');
$("#result").addClass('msg_error');
$("#result").fadeIn(1500);
}
});
});
PHP:
PHP:
$db = new DbConnector();
$db->connect();
$sql='SELECT grp.group_id, group_name, group_enabled, COUNT('.USER_TBL.'.id) AS users, grp.created, grp.updated '
.'FROM '.GROUP_TBL.' grp '
.'LEFT JOIN members USING(group_id) '
.'WHERE grp.group_id ='.$group_id.' GROUP BY grp.group_id';
$result = $db->query($sql);
$row = mysql_fetch_array($result);
$users = $row['users'];
if(!$users == '0'){
$return["json"] = json_encode($return);
echo json_encode(array('status' => 'error','message'=> 'There are users in this group'));
}else{
$sql2= 'DELETE FROM '.GROUP_TBL.' WHERE group_id='.$group_id.'';
$result = $db->query($sql2);
if(!$result){
echo json_encode(array('status' => 'error','message'=> 'The group has not been removed'));
}else{
echo json_encode(array('status' => 'success','message'=> 'The group has been removed'));
}
}
JSON Result from firebug:
firebug的JSON结果:
{"status":"success","message":"success message"}
AJAX Displays the JSON result as Undefined and I dont have a clue why. I have tried displaying adding dataType='json'
and datatype='json'
. I have also tried changing it to data.status
and data['status']
: still no joy though.
AJAX将JSON结果显示为未定义的,我不知道为什么。我尝试过显示添加数据类型='json'和数据类型='json'。我也尝试过把它改成data。状态和数据['状态']:仍然没有快乐。
Any help would be really appreciated.
如有任何帮助,我们将不胜感激。
5 个解决方案
#1
40
Make it dataType
instead of datatype
.
使它成为数据类型而不是数据类型。
And add below code in php as your ajax request is expecting json and will not accept anything, but json.
并且在php中添加下面的代码,因为您的ajax请求期望的是json,它不接受任何东西,只接受json。
header('Content-Type: application/json');
Correct Content type for JSON and JSONP
纠正JSON和JSONP的内容类型
The response visible in firebug is text data. Check Content-Type
of the response header to verify, if the response is json. It should be application/json
for dataType:'json'
and text/html
for dataType:'html'
.
firebug中可见的响应是文本数据。如果响应是json,请检查响应头的内容类型以进行验证。数据类型应该是application/json:'json',数据类型应该是text/html:'html'。
#2
3
I recommend you use:
我推荐你使用:
var returnedData = JSON.parse(data);
to convert the JSON string (if it is just text) to a JavaScript object.
将JSON字符串(如果只是文本)转换为JavaScript对象。
#3
2
try to send content type header from server use this just before echoing
尝试从服务器发送内容类型头,在回显之前使用这个
header('Content-Type: application/json');
#4
2
Use parseJSON jquery method to covert string into object
使用parseJSON jquery方法将字符串转换为对象
var objData = jQuery.parseJSON(data);
Now you can write code
现在您可以编写代码了
$('#result').html(objData .status +':' + objData .message);
#5
1
Your datatype is wrong, change datatype for dataType.
您的数据类型错误,请为数据类型更改数据类型。
#1
40
Make it dataType
instead of datatype
.
使它成为数据类型而不是数据类型。
And add below code in php as your ajax request is expecting json and will not accept anything, but json.
并且在php中添加下面的代码,因为您的ajax请求期望的是json,它不接受任何东西,只接受json。
header('Content-Type: application/json');
Correct Content type for JSON and JSONP
纠正JSON和JSONP的内容类型
The response visible in firebug is text data. Check Content-Type
of the response header to verify, if the response is json. It should be application/json
for dataType:'json'
and text/html
for dataType:'html'
.
firebug中可见的响应是文本数据。如果响应是json,请检查响应头的内容类型以进行验证。数据类型应该是application/json:'json',数据类型应该是text/html:'html'。
#2
3
I recommend you use:
我推荐你使用:
var returnedData = JSON.parse(data);
to convert the JSON string (if it is just text) to a JavaScript object.
将JSON字符串(如果只是文本)转换为JavaScript对象。
#3
2
try to send content type header from server use this just before echoing
尝试从服务器发送内容类型头,在回显之前使用这个
header('Content-Type: application/json');
#4
2
Use parseJSON jquery method to covert string into object
使用parseJSON jquery方法将字符串转换为对象
var objData = jQuery.parseJSON(data);
Now you can write code
现在您可以编写代码了
$('#result').html(objData .status +':' + objData .message);
#5
1
Your datatype is wrong, change datatype for dataType.
您的数据类型错误,请为数据类型更改数据类型。