大端小端简单测试

//bigdien or
  DWORD wd = 0x22;   //unsigned long 32位机器上是4个字节
  if( *((BYTE *)&wd) == 0x22 )       //BYTE unsigned char 1个字节
    AfxMessageBox(_T("Small-Endian"));
  else
    AfxMessageBox(_T("Big-Endian"));

这是VC中的测试。。。

例外一个完整的C程序如下：

/*
 * file: endian.c
 * descriptio: test our machine is big-endian or small-endian
 */

#include <stdio.h>

int main(int argc, char *argv[])
{
  union tagwt{
    int a;
    short b;
  }wt;

  wt.a = 0x11223344;

  //sizeof(wt)=4,sizeof(int)=4,sizeof(short)=2
  printf("sizeof(wt)=%d,sizeof(int)=%d,sizeof(short)=%d\n", sizeof(wt), sizeof(int), sizeof(short));

  if (wt.b == 0x3344)
    printf("small-endian\n");
  else if(wt.b == 0x1122)
    printf("big-endian\n");
  else
    printf("what's the fucking!");
}