a=[1,1,1,2,2,2,2,6,5,5,5,5]
num=[]
for i in a:
s = a.count(i)
num.append(s)
num1 = sorted(num,reverse=True)
num2=list(set(num1))
num2.sort(key=num1.index)
num3=[]
for x in num2:
for i in a:
if x ==a.count(i):
num3.append(i)
else:
pass
num4=[]
for j in num3:
if j not in num4:
num4.append(j)
print(num4)