元组列表中的唯一项列表

I have a list of tuples like this: mylist = [(1,2,3),(6,1,1),(7,8,1),(3,4,5)]. If I use the list comprehension slist = [item for sublist in mylist for item in sublist], I could get slist = [1,2,3,6,1,1,7,8,1,3,4,5].

我有一个像这样的元组列表：mylist = [（1,2,3），（6,1,1），（7,8,1），（3,4,5）]。如果我使用列表理解slist = [子列表中的项目为mylist中的子项列表]，我可以得到slist = [1,2,3,6,1,1,7,8,1,3,4,5] 。

How should I modify if I need only unique elements in slist like this [1,2,3,6,7,8,4,5]?

如果我只需要像[1,2,3,6,7,8,4,5]这样的slist中的唯一元素，我应该如何修改？

4 个解决方案

#1

You can actually make your first part a bit easier by using itertools.chain.from_iterable and then passing the result to set, which will only retain the unique elements:

通过使用itertools.chain.from_iterable然后将结果传递给set，您实际上可以使您的第一部分更容易，这将只保留唯一元素：

>>> mylist = [(1,2,3),(6,1,1),(7,8,1),(3,4,5)]
>>> import itertools
>>> set(itertools.chain.from_iterable(mylist))
set([1, 2, 3, 4, 5, 6, 7, 8])

#2

Use a set instead of a list.

使用集而不是列表。

set(slist)

If you really need it as a list then you can convert it back to a list:

如果您确实需要它作为列表，那么您可以将其转换回列表：

slist = list(set(slist))

Note that this conversion won't preserve the original order of the elements. If you need the same order you can use this instead:

请注意，此转换不会保留元素的原始顺序。如果您需要相同的订单，您可以使用它：

>>> result = []
>>> seen = set()
>>> for innerlist in mylist:
        for item in innerlist:
            if not item in seen:
                seen.add(item)
                result.append(item)
>>> result
[1, 2, 3, 6, 7, 8, 4, 5]

#3

import itertools
chain = itertools.chain(*mylist)
print(set(chain))

taken from Flattening a shallow list in Python and adapted for use in this question.

摘自在Python中展平浅表并适用于此问题。

#4

You should use python sets http://docs.python.org/library/sets.html

你应该使用python sets http://docs.python.org/library/sets.html

set(yourlist)

it will do the trick

它会做的伎俩

#1