I got strings which go:
我得到的字符串：
abc123abc123abc123
abc123abc123abc123
abc123
ABC123
abc123abc123abc123abc123abc123abc123
abc123abc123abc123abc123abc123abc123
etc (varying units of abc123 which I don't know the length of repeat)
等（abc123的不同单位，我不知道重复的长度）
The task is to extract the first 1 and first a and the last c and last 3. Is it possible to do it with 1 regex and how exactly if it is possible? I kept count of the repeating units and based on the count I have been able to perform the task with a few regex, but would like to use one regex if possible. Thanks
任务是提取第一个1和第一个a和最后一个c和最后一个3.是否可以使用1个正则表达式以及它是如何实现的？我一直在计算重复单位，根据计数，我已经能够用一些正则表达式执行任务，但是如果可能的话，我想使用一个正则表达式。谢谢
Edit: In the real situation. It is more like a:(a number)bc:(a number)1:(a number)23:(a number) etc and I have to capture the first a number, the first 1 number, the last c number and the last 3 number.
编辑：在实际情况。它更像是:(一个数字）bc :(一个数字）1 :(一个数字）23 :(一个数字）等我必须捕获第一个数字，前1个数字，最后一个c数字和最后3个号码。
Jeff
杰夫
1 个解决方案
#1
3
This is easiest done using two regexen. "^(a)bc(1)23" and "ab(c)12(3)$". It may be possible to merge these two, but the regular expression will get pretty unreadable.
这是使用两个regexen最简单的方法。 “^（a）bc（1）23”和“ab（c）12（3）$”。有可能合并这两个，但正则表达式将变得非常难以理解。
#1
3
This is easiest done using two regexen. "^(a)bc(1)23" and "ab(c)12(3)$". It may be possible to merge these two, but the regular expression will get pretty unreadable.
这是使用两个regexen最简单的方法。 “^（a）bc（1）23”和“ab（c）12（3）$”。有可能合并这两个，但正则表达式将变得非常难以理解。