I have a JavaScript function that tests a string and validates if it contains letters, numbers, and a few special characters, including the characters %20 (space) %27 (apostrophe).
我有一个JavaScript函数来测试字符串并验证它是否包含字母,数字和一些特殊字符,包括字符%20(空格)%27(撇号)。
My current RegEx fails as it allows other characters like %3
我当前的RegEx失败,因为它允许其他字符,如%3
I would like to fail on any match of %3 in the string. Better still, I would like to only match on %20 and/or %27 as a group.
我想在字符串中的%3匹配失败。更好的是,我想只在%20和/或%27上匹配。
My RegEx is
我的RegEx是
^[0-9a-zA-Z\%20\-_:.,!\/\\%27]+$
I want this to match
我想要这个匹配
Employee%27s%20Saved
But fail something like
但是失败了
%3Emplo%3yee%27s%20Saved%3
2 个解决方案
#1
0
Update to @MohaMad comment:
更新@MohaMad评论:
^(?:[0-9a-zA-Z-_:.,!/\\]|%20|%27)+$
By using a non-capturing group it will result with full match only.
通过使用非捕获组,它将仅与完全匹配。
#2
0
Try using a 'non-capturing group' (?!...).
尝试使用“非捕获组”(?!...)。
You should try something like this: ^(\w*(?!\%3)\w*(?:\%27|\%20)\w*)+$
你应该尝试这样的事情:^(\ w *(?!\%3)\ w *(?:\%27 | \%20)\ w *)+ $
#1
0
Update to @MohaMad comment:
更新@MohaMad评论:
^(?:[0-9a-zA-Z-_:.,!/\\]|%20|%27)+$
By using a non-capturing group it will result with full match only.
通过使用非捕获组,它将仅与完全匹配。
#2
0
Try using a 'non-capturing group' (?!...).
尝试使用“非捕获组”(?!...)。
You should try something like this: ^(\w*(?!\%3)\w*(?:\%27|\%20)\w*)+$
你应该尝试这样的事情:^(\ w *(?!\%3)\ w *(?:\%27 | \%20)\ w *)+ $