如何从Hex NSString中获取十进制的int

I would like to get a dec value from a Hex-encoded string, for examples: A->10, B->11,etc. and I coded as the following

我想从十六进制编码的字符串中获取十进制值,例如:A-> 10,B-> 11等。我编码如下

NSString *tempNumber;
tempNumber=number.text; 
NSScanner *scanner=[NSScanner scannerWithString:tempNumber];
unsigned int temp;
[scanner scanHexInt:temp];
NSLog(@"%@:%d",tempNumber,temp);

but the NSLog output isn't what I perfer..

但NSLog输出不是我所知道的..

2012-01-24 01:34:57.703 TestingUnit[34861:f803] 4:-1073750472
2012-01-24 01:35:01.133 TestingUnit[34861:f803] 6:-1073750408
2012-01-24 01:35:01.983 TestingUnit[34861:f803] 2:-1073750408
2012-01-24 01:35:02.414 TestingUnit[34861:f803] 1:-1073750408

could someone tell me how can I solve this????

有人能告诉我怎么解决这个问题????

1 个解决方案

#1

You should use

你应该用

[scanner scanHexInt:&temp];

scanHexInt: expects a pointer, not a value.

scanHexInt:期望一个指针,而不是一个值。