Basically, I am running:
基本上,我正在运行:
nohup ./executable &> /tmp/out.log &
In order to make sure the process is running I ran the command:
为了确保进程正在运行,我运行了命令:
tail -f /tmp/out.log
But the only thing I can get from tail is "nohup: ignoring input", and once killing the process that previously started I can see the contents of out.log
但我唯一可以从尾巴获得的是“nohup:忽略输入”,一旦杀死之前开始的进程,我可以看到out.log的内容
2 个解决方案
#1
5
Run your program as:
运行您的程序:
nohup stdbuf -oL ./executable &> /tmp/out.log &
stdbuf can change the default buffering.
stdbuf可以更改默认缓冲。
#2
4
Your executable is using buffered output, so you will only see something with tail if more than one block of output is produced. The size of such a block will be 4k or more.
您的可执行文件使用缓冲输出,因此如果生成多个输出块,您将只看到带尾部的内容。这种块的大小将是4k或更多。
If you wrote the executable yourself, change the output to line buffered or to not buffered.
如果您自己编写了可执行文件,请将输出更改为行缓冲或未缓冲。
#1
5
Run your program as:
运行您的程序:
nohup stdbuf -oL ./executable &> /tmp/out.log &
stdbuf can change the default buffering.
stdbuf可以更改默认缓冲。
#2
4
Your executable is using buffered output, so you will only see something with tail if more than one block of output is produced. The size of such a block will be 4k or more.
您的可执行文件使用缓冲输出,因此如果生成多个输出块,您将只看到带尾部的内容。这种块的大小将是4k或更多。
If you wrote the executable yourself, change the output to line buffered or to not buffered.
如果您自己编写了可执行文件,请将输出更改为行缓冲或未缓冲。