How can I print a character N number of times using std::cout without looping?
如何在没有循环的情况下使用std :: cout打印字符N次？
Is there a way to move the text cursor back to nullify the effect of std::cout << std::endl;? i.e. to move up a line (say we never printed anything after doing the std::cout << std::endl; operation).
有没有办法将文本光标移回以取消std :: cout << std :: endl;？的效果？即向上移动一行（假设在执行std :: cout << std :: endl;操作后我们从未打印过任何内容）。
3 个解决方案
#1
55
std::cout << std::string(100, '*') << std::endl;
To move a line up, you have to resort to terminal escapes (assuming that isatty() indicates that you are running on one).
要移动一行，您必须求助于终端转义（假设isatty（）表示您正在运行一个）。
#2
12
std::cout << std::setfill(the_char) << std::setw(100) << "";
#3
0
is there a way to back our way to nullify the effect of cout << endl; i.e. to move up a line(say we never printed anything after doing the cout << endl; operation) Thank you so much!
有没有办法支持我们的方法来消除cout << endl的影响;即向前移动一条线（假设我们在做完cout << endl;操作后从未打印过任何东西）非常感谢你！
Use the ternary operator (or an if statement if you refer) ... something like ...
使用三元运算符（如果你引用的话，还是if语句）......类似......
void PrintCharNtimes(char chatToPrint; int numTimes)
{
std::cout << std::string(numTimes, chatToPrint) << (numTimes > 0) ? std::endl : ;
}
#1
55
std::cout << std::string(100, '*') << std::endl;
To move a line up, you have to resort to terminal escapes (assuming that isatty() indicates that you are running on one).
要移动一行，您必须求助于终端转义（假设isatty（）表示您正在运行一个）。
#2
12
std::cout << std::setfill(the_char) << std::setw(100) << "";
#3
0
is there a way to back our way to nullify the effect of cout << endl; i.e. to move up a line(say we never printed anything after doing the cout << endl; operation) Thank you so much!
有没有办法支持我们的方法来消除cout << endl的影响;即向前移动一条线（假设我们在做完cout << endl;操作后从未打印过任何东西）非常感谢你！
Use the ternary operator (or an if statement if you refer) ... something like ...
使用三元运算符（如果你引用的话，还是if语句）......类似......
void PrintCharNtimes(char chatToPrint; int numTimes)
{
std::cout << std::string(numTimes, chatToPrint) << (numTimes > 0) ? std::endl : ;
}