Basically, I have some code that asks a user to input a comma-separated list of currencies and 2 dates. I want to take these currencies, and write it to a CSV file in the following format:
基本上,我有一些代码要求用户输入以逗号分隔的货币列表和2个日期。我想采用这些货币,并按以下格式将其写入CSV文件:
Date, Curr1, Curr2, Curr3, ... , Currn
---, x, x, x, ..., n
---, x, x, x, ..., n
Where x is the exchange rate for the currency on the given date. I have tried using csv.writer like this:
其中x是给定日期货币的汇率。我试过像这样使用csv.writer:
writer = ex.csv.writer(f, delimiter=',')
writer.writerow(['Date', codes])
for i in range(delta.days + 1):
date = real_date + ex.timedelta(days=i)
rates = exchrates(date) #function fetches all rates on given date, returns dict
for j in codes:
writer.writerow([date, rates[j.upper()]])
but it doesn't write to the file how I would like, rather like this:
但它不会写入我想要的文件,而是像这样:
Date,['RSD', 'GBP']
2008-04-11,51.586749
2008-04-11,0.506908
2008-04-12,51.586749
2008-04-12,0.506674
putting each currency's value on a new row, whereas I want it like:
将每种货币的价值放在一个新行上,而我希望它像:
Date,RSD,GBP
2008-04-11,51.586749,0.506908
2008-04-12,51.586749,0.506674
I am a beginner to Python so apologies if this is trivial. Any help would be greatly appreciated.
我是Python的初学者,如果这是微不足道的话,请道歉。任何帮助将不胜感激。
Thanks.
3 个解决方案
#1
Well. The output is just, what you actually programmed it to be.
好。输出就是,你实际编程的是什么。
With writer.writerow()
you should write only a list of data. Try this:
使用writer.writerow(),您应该只写一个数据列表。试试这个:
writer = ex.csv.writer(f, delimiter=',')
writer.writerow(['Date'] + codes) # codes seems to be a list, so just append it
for i in range(delta.days + 1):
date = real_date + ex.timedelta(days=i)
rates = exchrates(date)
writer.writerow([date] + [rates[j.upper()] for j in codes]) # only one line
#2
You're writing the exchange rate for each currency on a new line because in the inner for
cycle you're iterating through the list ot codes
and you're performing a write operation for each code. Instead of
您正在为新行编写每种货币的汇率,因为在内部循环中,您将遍历列表或代码,并且您正在为每个代码执行写入操作。代替
for j in codes:
writer.writerow([date, rates[j.upper()]])
you should do something like this:
你应该做这样的事情:
new_row = [date]
for j in codes:
new_row.append(rates[j.upper()])
writer.writerow(new_row)
#3
writerow
writes just that: an entire row. You need to build the row using codes
and make one call.
作家写道:整整一行。您需要使用代码构建行并进行一次调用。
for i in range(delta.days + 1):
date = real_date + ex.timedelta(days=i)
rates = exchrates(date) #function fetches all rates on given date, returns dict
writer.writerow([date] + [rates[j.upper()] for j in codes])
#1
Well. The output is just, what you actually programmed it to be.
好。输出就是,你实际编程的是什么。
With writer.writerow()
you should write only a list of data. Try this:
使用writer.writerow(),您应该只写一个数据列表。试试这个:
writer = ex.csv.writer(f, delimiter=',')
writer.writerow(['Date'] + codes) # codes seems to be a list, so just append it
for i in range(delta.days + 1):
date = real_date + ex.timedelta(days=i)
rates = exchrates(date)
writer.writerow([date] + [rates[j.upper()] for j in codes]) # only one line
#2
You're writing the exchange rate for each currency on a new line because in the inner for
cycle you're iterating through the list ot codes
and you're performing a write operation for each code. Instead of
您正在为新行编写每种货币的汇率,因为在内部循环中,您将遍历列表或代码,并且您正在为每个代码执行写入操作。代替
for j in codes:
writer.writerow([date, rates[j.upper()]])
you should do something like this:
你应该做这样的事情:
new_row = [date]
for j in codes:
new_row.append(rates[j.upper()])
writer.writerow(new_row)
#3
writerow
writes just that: an entire row. You need to build the row using codes
and make one call.
作家写道:整整一行。您需要使用代码构建行并进行一次调用。
for i in range(delta.days + 1):
date = real_date + ex.timedelta(days=i)
rates = exchrates(date) #function fetches all rates on given date, returns dict
writer.writerow([date] + [rates[j.upper()] for j in codes])