I have worked in SOAP message to get LoginToken from Webservice, and store the LoginToken in String and used System.out.println(LoginToken);
to print. This prints [wdsd34svdf], but I want only wdsd34svdf so, how to remove square bracket. please any one help me.
我使用SOAP消息从Webservice获取LoginToken,并将LoginToken存储在String中并使用System.out.println(LoginToken);打印。打印[wdsd34svdf],但我只想要wdsd34svdf,如何删除方括号。请任何人帮助我。
Thanks
谢谢
Example:
例:
String LoginToken=getName().toString();
System.out.println("LoginToken" + LoginToken);
Output: [wdsd34svdf] I want wdsd34svdf
输出:[wdsd34svdf]我想要wdsd34svdf
8 个解决方案
#1
121
It's easy, You need to find index of [ and ] then substring. (Here [ is always at start and ] is at end) ,
这很简单,你需要找到[和]然后子串的索引。 (这里[始终在开始,]在结束时),
String loginToken="[wdsd34svdf]";
System.out.println(loginToken.substring(1, loginToken.length()-1));
#2
11
You can always use substring
:
您始终可以使用子字符串:
String loginToken = getName().toString();
loginToken = loginToken.substring(1, loginToken.length() - 1);
#3
10
This is generic solution:
这是通用解决方案:
str.replaceAll("^.|.$", "")
#4
7
Another solution for this issue is use commons-lang (since version 2.0) StringUtils.substringBetween(String str, String open, String close)
method. Main advantage is that it's null safe operation.
此问题的另一个解决方案是使用commons-lang(自2.0版本起)StringUtils.substringBetween(String str,String open,String close)方法。它的主要优点是无效安全操作。
StringUtils.substringBetween("[wdsd34svdf]", "[", "]"); // returns wdsd34svdf
StringUtils.substringBetween(“[wdsd34svdf]”,“[”,“]”); //返回wdsd34svdf
#5
4
I had a similar scenario, and I thought that something like
我有类似的情况,我觉得有点像
str.replaceAll("\[|\]", "");
looked cleaner. Of course, if your token might have brackets in it, that wouldn't work.
看起来更干净当然,如果您的令牌中可能包含括号,则无效。
#6
0
This way you can remove 1 leading "[" and 1 trailing "]" character. If your string happen to not start with "[" or end with "]" it won't remove anything:
这样你就可以删除1个前导“[”和1个尾随“]”字符。如果您的字符串碰巧不以“[”开头或以“]结尾”,则不会删除任何内容:
str.replaceAll("^\\[|\\]$", "")
#7
0
StringUtils
's removeStart
and removeEnd
method help to remove string from start and end of a string.
StringUtils的removeStart和removeEnd方法有助于从字符串的开头和结尾删除字符串。
In this case we could also use combination of this two method
在这种情况下,我们也可以使用这两种方法的组合
String string = "[wdsd34svdf]";
System.out.println(StringUtils.removeStart(StringUtils.removeEnd(string, "]"), "["));
#8
-1
This will gives you basic idea
这将为您提供基本的想法
String str="";
String str1="";
Scanner S=new Scanner(System.in);
System.out.println("Enter the string");
str=S.nextLine();
int length=str.length();
for(int i=0;i<length;i++)
{
str1=str.substring(1, length-1);
}
System.out.println(str1);
#1
121
It's easy, You need to find index of [ and ] then substring. (Here [ is always at start and ] is at end) ,
这很简单,你需要找到[和]然后子串的索引。 (这里[始终在开始,]在结束时),
String loginToken="[wdsd34svdf]";
System.out.println(loginToken.substring(1, loginToken.length()-1));
#2
11
You can always use substring
:
您始终可以使用子字符串:
String loginToken = getName().toString();
loginToken = loginToken.substring(1, loginToken.length() - 1);
#3
10
This is generic solution:
这是通用解决方案:
str.replaceAll("^.|.$", "")
#4
7
Another solution for this issue is use commons-lang (since version 2.0) StringUtils.substringBetween(String str, String open, String close)
method. Main advantage is that it's null safe operation.
此问题的另一个解决方案是使用commons-lang(自2.0版本起)StringUtils.substringBetween(String str,String open,String close)方法。它的主要优点是无效安全操作。
StringUtils.substringBetween("[wdsd34svdf]", "[", "]"); // returns wdsd34svdf
StringUtils.substringBetween(“[wdsd34svdf]”,“[”,“]”); //返回wdsd34svdf
#5
4
I had a similar scenario, and I thought that something like
我有类似的情况,我觉得有点像
str.replaceAll("\[|\]", "");
looked cleaner. Of course, if your token might have brackets in it, that wouldn't work.
看起来更干净当然,如果您的令牌中可能包含括号,则无效。
#6
0
This way you can remove 1 leading "[" and 1 trailing "]" character. If your string happen to not start with "[" or end with "]" it won't remove anything:
这样你就可以删除1个前导“[”和1个尾随“]”字符。如果您的字符串碰巧不以“[”开头或以“]结尾”,则不会删除任何内容:
str.replaceAll("^\\[|\\]$", "")
#7
0
StringUtils
's removeStart
and removeEnd
method help to remove string from start and end of a string.
StringUtils的removeStart和removeEnd方法有助于从字符串的开头和结尾删除字符串。
In this case we could also use combination of this two method
在这种情况下,我们也可以使用这两种方法的组合
String string = "[wdsd34svdf]";
System.out.println(StringUtils.removeStart(StringUtils.removeEnd(string, "]"), "["));
#8
-1
This will gives you basic idea
这将为您提供基本的想法
String str="";
String str1="";
Scanner S=new Scanner(System.in);
System.out.println("Enter the string");
str=S.nextLine();
int length=str.length();
for(int i=0;i<length;i++)
{
str1=str.substring(1, length-1);
}
System.out.println(str1);