密码强度正则表达式与数字[重复]

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Regular Expression for Password Strength Validation 6 answers

密码强度验证的正则表达式6个答案

I'm working on a strength password test, and I'm trying to check if the password has upper, and lower, case characters. I'm using two regular expressions, and they're almost working; with the code just here:

我正在进行强度密码测试,我正在尝试检查密码是否包含大写和小写字符。我正在使用两个正则表达式,它们几乎正在工作;使用此处的代码:

    var upper = false;
    var lower = false;
    var upperCase= new RegExp('[^A-Z]');
    var lowerCase= new RegExp('[^a-z]');
    


    if (password.match(upperCase )){
        upper = true;    
    }
    if (password.match(lowerCase)){
        lower = true;
    }

When I'm typing numbers, or just a digit, like "1", upper and lower become true.

当我输入数字或只是一个数字,如“1”时,上下变为真。

I'm not really good with regex, did I made a mistake?

我对正则表达式不是很好,我犯了错误吗?

2 个解决方案

#1

Take a look at the following which uses test to return a Boolean of whether the password contains an upper case and a lower case. You will see how it tests both regexes against various passwords.

看看以下使用test来返回密码是否包含大写和小写的布尔值。您将看到它如何针对各种密码测试两个正则表达式。

    var upperCase= new RegExp('[A-Z]');
    var lowerCase= new RegExp('[a-z]');
    

function test(password) {
    return [ upperCase.test(password), lowerCase.test(password)];
  }

console.log(test("Abc"));
console.log(test("abc"));
console.log(test("123"));

#2

Unless you are paid per line of code; you could simply write:

除非你按行代码付款;你可以简单地写:

var upper = password.match(/[A-Z]/);
var lower = password.match(/[a-z]/);

This also fixes the bug in your code where you use [^] which negates the match (aka; your upperCase regexp match non-uppercase chars)

这也修复了你的代码中使用[^]的错误,它会使匹配失效(aka;你的upperCase regexp匹配非大写字符)

#1