Jquery中Ajax/Post同步和异步请求


01 1
异步请求：
02    1.1 $.ajax
03       $.ajax({
04                url : 'your url',
05                data:{name:value},
06                cache : false,
07                async : true,
08                type : "POST",
09                dataType : 'json/xml/html',
10                success : function (result){
11                    do something....
12                }
13            });
14    2 同步请求
15    2.1 $.ajax
16       $.ajax({
17                url : 'your url',
18                data:{name:value},
19                cache : false,
20                async : false,
21                type : "POST",
22                dataType : 'json/xml/html',
23                success : function (result){
24                    do something....
25                }
26            });
27    2.2 $.post
28      $.post(
29                'your url',
30                {name:value},
31                function(data) {
32                    do something...
33                },
34            'json/xml/html'
35            );
或者采用以下方法

在全局设置：

1 $.ajaxSetup({ 
2     async : false 
3 });
然后再使用post或get方法


1 $.get("register/RegisterState", {test : 12}, function(data, status) { 
2     if (status == "success") { 
3             data = eval("(" + data + ")"); 
4         aDataSet = data; 
5         alert("data is " + aDataSet); 
6     } else { 
7             alert("wrong"); 
8          } 
9 });