I am starting with
我开始了
http://myurl.com/helloworld.html","asdfa
and I am expecting after my regex is run
在我的正则表达式运行之后,我期待着
http://myurl.com/helloworld.html
I have the following php command
我有以下php命令
echo shell_exec("cat /tmp/urls | grep -Eo '^[^"]+'");
But I get no result when it runs.
但是当它运行时我没有得到任何结果。
When I run straight from command line with the following it works
当我直接从命令行运行时,它可以正常工作
$cat /tmp/urls | grep -Eo '^[^"]+'
1 个解决方案
#1
2
The \" in your php-string is actually ", so if you want it to actually be \" you should escape both the double-quote " and the slash \:
“你的php-string实际上是”,所以如果你想要它实际上是“你应该逃避双引号”和斜杠\:
echo shell_exec("cat /tmp/urls | grep -Eo '^[^\\\"]+'");
Another option is to use a single quote (and not double), however note that here you do need to escape the single-quotes inside the string:
另一种选择是使用单引号(而不是double),但请注意,在这里你需要转义字符串中的单引号:
echo shell_exec('cat /tmp/urls | grep -Eo \'^[^\"]+\'');
update
Based on the comment your code should be:
根据您的代码应该是注释:
echo shell_exec("cat /tmp/urls | grep -Eo '^[^\"]+'");
#1
2
The \" in your php-string is actually ", so if you want it to actually be \" you should escape both the double-quote " and the slash \:
“你的php-string实际上是”,所以如果你想要它实际上是“你应该逃避双引号”和斜杠\:
echo shell_exec("cat /tmp/urls | grep -Eo '^[^\\\"]+'");
Another option is to use a single quote (and not double), however note that here you do need to escape the single-quotes inside the string:
另一种选择是使用单引号(而不是double),但请注意,在这里你需要转义字符串中的单引号:
echo shell_exec('cat /tmp/urls | grep -Eo \'^[^\"]+\'');
update
Based on the comment your code should be:
根据您的代码应该是注释:
echo shell_exec("cat /tmp/urls | grep -Eo '^[^\"]+'");