列表()最多为1个参数(3个)

I want to get the vector like: v:[1.0, 2.0, 3.0]

我想要得到向量v:[1.0, 2.0, 3.0]

Here is my code:

这是我的代码:

class VECTOR(list) :
     def _init_ (self,x=0.0,y=0.0,z=0.0,vec=[]) :
          list._init_(self,[float(x),float(y),float(z)])
          if vec :
               for i in [0,1,2] :
                    self[i] = vec[i]

But when I typed: a = VECTOR(1,2,3) it went wrong like this:

但是当我输入:a =向量(1,2,3)就像这样:

TypeError: list() takes at most 1 argument (3 given)

TypeError: list()最多为1个参数(3个)

How can I dissolve it?

我该如何解散它?

2 个解决方案

#1

The problem is that you've misspelled the name of the constructor. Replace _init_ with __init__.

问题是，您错误地拼写了构造函数的名称。用__init__替换_init_。

Here's the fixed code:

这是固定的代码:

class VECTOR(list) :
     def __init__ (self,x=0.0,y=0.0,z=0.0,vec=[]) :
          list.__init__(self,[float(x),float(y),float(z)])
          if vec :
               for i in [0,1,2] :
                    self[i] = vec[i]

a = VECTOR(1,2,3)
print(a)

And the demonstration that it works:

它的作用是:

 % python test.py
[1.0, 2.0, 3.0]

I'd also like to give you a few additional comments:

我还想给你一些额外的评论:

you should fix the coding style according to PEP8 (that's a document every Python developer should read entirely);
您应该根据PEP8修复编码风格(这是每个Python开发人员应该完全阅读的文档);
you can probably do something more Pythonic (thanks Benjamin);
你可能会做一些更大的勾当(感谢本杰明);
inheritance is not the only way to do that, you can also use an attribute to store the list and define the relevant methods (thanks Veedrac);
继承并不是唯一的方法，您还可以使用属性来存储列表并定义相关的方法(谢谢Veedrac);
you could also use super (see paddyg's answer);
你也可以使用super(见paddyg的答案);

edit note: I've added to this solution the relevant advises found in the comments.

编辑注:我已经在注释中添加了相关的建议。

#2

-2

EDIT if you call using super(VECTOR, list).__init__() you don't need to pass self. ~~Also you need to pass 1,2,3 as a list [1,2,3]~~

编辑如果你使用super(VECTOR, list).__init__()你不需要通过self。你也需要把1 2 3作为一个列表[1,2,3]

#1