TypeError：__ init __（）需要4个位置参数，但是给出了5个

I have looked up similar questions, yet most problems are related to omitting the self argument in the __init__ definition.

我查找了类似的问题,但大多数问题都与省略__init__定义中的self参数有关。

Code:

class steamurl():

    baseurl = "http://api.steampowered.com/{0}/{1}/{2}/"

    def __init__(self, loc1, loc2, vnum, **options):
        self.loc1 = loc1
        self.loc2 = loc2
        self.vnum = vnum
        self.options = options

optionsdic = {
    'key': 'KEYHERE',
    'game_mode': 'all_pick',
    'min_players': '7'
    }

testurl = steamurl("IDOTA2Match_570", "GetMatchHistory", "v001", optionsdic)

However here my code was working fine before I added the "optionsdic" to the class. After adding it I get the type error in the title. Am I using **kwargs incorrectly as an argument?

然而,在我向类中添加“optionsdic”之前,我的代码工作正常。添加后,我在标题中得到类型错误。我错误地使用** kwargs作为参数吗?

3 个解决方案

#1

You need to use ** to apply optionsdic as keyword arguments:

您需要使用**将optionsdic作为关键字参数应用:

testurl = steamurl("IDOTA2Match_570", "GetMatchHistory", "v001", **optionsdic)

otherwise it is just another positional argument passing in a dictionary object.

否则它只是传入字典对象的另一个位置参数。

This mirrors the syntax in the function signature.

这反映了函数签名中的语法。

#2

If you want to pass the contents of optionsdic as separate keyword arguments, you need to use ** unpacking:

如果要将optionsdic的内容作为单独的关键字参数传递,则需要使用**解包:

testurl = steamurl("IDOTA2Match_570", "GetMatchHistory", "v001", **optionsdic)

#3

You should call using **:

你应该使用**来打电话:

testurl = steamurl("IDOTA2Match_570", "GetMatchHistory", "v001", optionsdic)

This will unpack the dictionary into separate keyword arguments. In __init__ the keyword arguments will then be packed into a dictionary due to **options.

这会将字典解压缩为单独的关键字参数。在__init__中,由于**选项,关键字参数将被打包到字典中。

#1