如何在python中将字典项作为函数参数传递?(复制)

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这个问题已经有了答案:

Passing a dictionary to a function in python as keyword parameters 4 answers
将字典作为关键字参数4的答案传递给python中的函数

My code

我的代码

1st file:

文件1:

data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}
my_function(*data)

2nd file:

文件2:

my_function(*data):
    schoolname  = school
    cityname = city
    standard = standard
    studentname = name

in the above code, only keys of "data" dictionary were get passed to my_function(), but i want key-value pairs to pass. How to correct this ?

在上面的代码中，只有“data”字典的键被传递给my_function()，但是我想传递键-值对。如何改正?

I want the my_function() to get modified like this

我想要像这样修改my_function()

my_function(school='DAV', standard='7', name='abc', city='delhi')

and this is my requirement, give answers according to this

这是我的要求，根据这个给出答案

EDIT: dictionary key class is changed to standard

编辑:字典键类被更改为标准

3 个解决方案

#1

If you want to use them like that, define the function with the variable names as normal (but use klass for class, you can't use reserved words):

如果你想这样使用它们，用变量名来定义函数(但是使用klass作为类，你不能使用保留字):

def my_function(school, city, klass, name):
    schoolname  = school
    cityname = city
    standard = klass
    studentname = name

Now (as long as you rename class to klass in your dictionary) you can use ** when you call the function:

现在(只要在字典中将类重命名为klass)，就可以在调用函数时使用**:

my_function(**data)

and it will work as you want.

你想怎么做就怎么做。

#2

*data interprets arguments as tuples, instead you have to pass **data which interprets the arguments as dictionary.

*数据将参数解释为元组，相反，您必须传递**数据，该数据将参数解释为字典。

data = {'school':'DAV', 'class': '7', 'name': 'abc', 'city': 'pune'}


def my_function(**data):
    schoolname  = data['school']
    cityname = data['city']
    standard = data['class']
    studentname = data['name']

You can call the function like this:

你可以这样调用函数:

my_function(**data)

#3

You can just pass it

你可以通过它

def my_function(my_data):
    my_data["schoolname"] = "something"
    print my_data

or if you really want to

或者如果你真的想

def my_function(**kwargs):
    kwargs["schoolname"] = "something"
    print kwargs

#1