When I write setters for instance methods, I use this to disambiguate between the instance variable and the parameter:
当我为实例方法编写setter时,我使用它来消除实例变量和参数之间的歧义:
public void setValue(int value) {
this.value = value;
}
So, what do I do when value is a class variable (static) instead of a member of an instance?
那么,当value是类变量(静态)而不是实例的成员时,我该怎么办?
private static int value = 7;
public static void setValue(int value) {
value = value; // compile fails; ambiguous
}
1 个解决方案
#1
Use <classname>.value = value;
使用
#1
Use <classname>.value = value;
使用