将2个数据帧与多个不同列名的列合并

I need help with a merge(vlookup) problem that I can not solve. I have 2 data frames I would like to merge, in addition they also have different column names. My real datasets have many columns and that why its a hard for me to come up with a solution. I have tried the merge function but I can not figure out how to do it on multiple columns with different names. I would like to explicitly specify the column names using something like:

我需要帮助解决我无法解决的合并(vlookup)问题。我有2个数据框我想合并,此外它们也有不同的列名。我的真实数据集有很多列,这就是为什么我很难找到解决方案。我已经尝试了合并功能,但我无法弄清楚如何在具有不同名称的多个列上执行此操作。我想使用类似的东西显式指定列名:

output <- merge(df1, df.vlookup, by.x=????, by.y=???, ) #just where I am today

Here is a very simplified example

这是一个非常简单的例子

id<-c(2,4,6,8,10,12,14,16,18,20,22,24,26,28)
bike <- c(1,3,2,1,1,1,2,3,2,3,1,1,1,1)
size <- c(1,2,1,2,1,2,1,2,1,2,1,2,1,2)
color <-c (10,11,13,15,12,12,12,11,11,14,12,11,10,10)
price <- c(1,2,2,2,1,3,1,1,2,1,2,1,2,1)


df1 <- data.frame(id,bike,size,color,price)

   id bike size color price
1   2    1    1    10     1
2   4    3    2    11     2
3   6    2    1    13     2
4   8    1    2    15     2
5  10    1    1    12     1
6  12    1    2    12     3
7  14    2    1    12     1
8  16    3    2    11     1
9  18    2    1    11     2
10 20    3    2    14     1
11 22    1    1    12     2
12 24    1    2    11     1
13 26    1    1    10     2
14 28    1    2    10     1


b1<-c(1,2,3)
b2<-c("Alan", "CCM", "Basso")
s1 <- c(1,2)
s2 <- c("L","S")
c1<-c(10,11,12,13,14,15)
c2 <-c("black","blue","green","red","pink")
p1<- c(1,2,3)
p2<- c(1000,2000,3000)

#trick for making a dataframe with unequal vector length
na.pad <- function(x,len){
  x[1:len]
}

makePaddedDataFrame <- function(l,...){
  maxlen <- max(sapply(l,length))
  data.frame(lapply(l,na.pad,len=maxlen),...)
}

df.vlookup <- makePaddedDataFrame(list(b1=b1,b2=b2,s1=s1,s2=s2,c1=c1,c2=c2,p1=p1,p2=p2))

> df.vlookup
  b1    b2 s1   s2 c1    c2 p1   p2
1  1  Alan  1    L 10 black  1 1000
2  2   CCM  2    S 11  blue  2 2000
3  3 Basso NA <NA> 12 green  3 3000
4 NA  <NA> NA <NA> 13   red NA   NA
5 NA  <NA> NA <NA> 14  pink NA   NA
6 NA  <NA> NA <NA> 15  <NA> NA   NA

Here is a dataframe that I would like to end up with:

这是一个我想最终得到的数据框:

> df.final
   id bike    b2 size s2 color    c2 price
1   2    1  Alan    1  L    10 black     1
2   4    3 Basso    2  S    11  blue     2
3   6    2   CCM    1  L    13   red     2
4   8    1  Alan    2  S    15  #N/A     2
5  10    1  Alan    1  L    12 green     1
6  12    1  Alan    2  S    12 green     3
7  14    2   CCM    1  L    12 green     1
8  16    3 Basso    2  S    11  blue     1
9  18    2   CCM    1  L    11  blue     2
10 20    3 Basso    2  S    14  pink     1
11 22    1  Alan    1  L    12 green     2
12 24    1  Alan    2  S    11  blue     1
13 26    1  Alan    1  L    10 black     2
14 28    1  Alan    2  S    10 black     1   

Really appreciate some help on this...

真的很感激这方面的一些帮助......

1 个解决方案

#1

I don't think a single data frame for lookup values is the right approach. What about using named vectors?

我不认为查找值的单个数据框是正确的方法。那么使用命名向量呢?

For example:

bike_names <- c("Alan" = 1, "CCM" = 2, "Basso" = 3)
df1$b2 <- names(bike_names[ df1$bike ])

If using data frames, put each lookup table in a separate data frame.

如果使用数据帧,请将每个查找表放在单独的数据框中。

lookup <- list(
  bike = data.frame( bike = c(1, 2, 3), bike_name = c("Alan", "CCM", "Basso")),
  size = data.frame(size = c(1, 2),  size_name = c("L", "S")),
  color = data.frame(color = c(10, 11, 12, 13, 14, 15), color_name = c("black", "blue", "green", "red", "pink", NA)),
  price = data.frame(price = c(1, 2, 3), price_name = c(1000, 2000, 3000))
)

And use it with merge:

并使用它与合并:

Reduce(merge, c(data = list(df1), lookup))

Or use dplyr and joins:

或者使用dplyr和join:

library(dplyr)

df1 %>%
  left_join(lookup$bike, by = c("bike")) %>%
  left_join(lookup$size, by = c("size")) %>%
  left_join(lookup$color, by = c("color")) %>%
  left_join(lookup$price, by = c("price"))

Update

But if you really want to start from the df.vlookup data frame, you can convert it to a list of data frames like this:

但是,如果您真的想从df.vlookup数据框开始,可以将其转换为数据框列表,如下所示:

lookup <- lapply(seq(1, to = ncol(df.vlookup), by = 2), function(i) {
  setNames(df.vlookup[,c(i,i+1)], c(names(df1)[i/2+2], names(df.vlookup)[i+1]))
})

And use it in a multiple merge:

并在多次合并中使用它:

Reduce(merge, c(data = list(df1), lookup))

NOTE: When creating lookup list there are some assumptions about column order in df1 and in df.vlookup

注意:创建查找列表时,df1和df.vlookup中的列顺序有一些假设