I need to return average for each of 12 columns I have in a table in DB. MySQL allows one to get average for one column only. The following query (for one column) works:
我需要为DB中的一个表中的12列中的每一列返回平均值。 MySQL允许只获得一列的平均值。以下查询(对于一列)有效:
SELECT station_id, AVG(jan) AS avg_jan
FROM `climate_data`
WHERE element_name = "Temp_mean_mly" AND jan <> -999999
GROUP BY station_id
and the following (for multiple columns) does not (I get syntax error):
和以下(对于多列)不(我得到语法错误):
SELECT station_id, AVG(jan) AS avg_jan, AVG(feb) AS avg_feb, ... ,
AVG(dec) AS avg_dec
FROM `climate_data`
WHERE element_name = "Temp_mean_mly"
AND jan <> -999999
AND feb <> -999999
AND ...
AND dec <> -999999
GROUP BY station_id
Do I have to use 12 sub-queries to achieve the result I need?
我是否必须使用12个子查询来实现我需要的结果?
Thanks for your help
谢谢你的帮助
1 个解决方案
#1
2
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'dec)
1064 - 您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册,以便在'dec'附近使用正确的语法
dec is a reserved MySQL keyword; changing it to `dec` in your query would probably fix that error for you :).
dec是一个保留的MySQL关键字;在查询中将其更改为“dec”可能会为您修复该错误:)。
Edit: note that you're also using it in the WHERE clause; it might work there (as it's unlogical for MySQL to find a keyword there), but keep it in mind that you might also have to escape that one :)
编辑:请注意您也在WHERE子句中使用它;它可能在那里工作(因为MySQL在那里找到一个关键字是不合逻辑的),但请记住,你可能还必须逃避那个:)
#1
2
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'dec)
1064 - 您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册,以便在'dec'附近使用正确的语法
dec is a reserved MySQL keyword; changing it to `dec` in your query would probably fix that error for you :).
dec是一个保留的MySQL关键字;在查询中将其更改为“dec”可能会为您修复该错误:)。
Edit: note that you're also using it in the WHERE clause; it might work there (as it's unlogical for MySQL to find a keyword there), but keep it in mind that you might also have to escape that one :)
编辑:请注意您也在WHERE子句中使用它;它可能在那里工作(因为MySQL在那里找到一个关键字是不合逻辑的),但请记住,你可能还必须逃避那个:)