I have 2 tables that look like this:
我有2个表看起来像这样:
CREATE TABLE places(
id INTEGER PRIMARY KEY AUTOINCREMENT,
type TEXT
...
)
CREATE TABLE meta(
id INTEGER PRIMARY KEY AUTOINCREMENT,
place INTEGER NOT NULL,
key TEXT NOT NULL,
value TEXT,
FOREIGN KEY(place) REFERENCES places(id) ON DELETE CASCADE
)
The meta table is a "eav" like table.
元表是一个像表一样的“eav”。
Now I want to select all records that have "lat" and "lng" attributes and join lat" and "lng" with a space in the result
现在我想选择所有具有“lat”和“lng”属性的记录,并在结果中用空格连接lat“和”lng“
This is my current query
这是我目前的查询
SELECT p.id, m1.value || " " || m2.value FROM places p
JOIN meta m1 ON m1.place = p.id
JOIN meta m2 ON m2.place = p.id
WHERE p.type IN ("1")
AND m1.key = "lat"
AND m2.key = "lng";
It appears it works. But is this really correct? Can I do it using a single join?
它似乎有效。但这真的是对的吗?我可以使用一次加入吗?
1 个解决方案
#1
0
Single quotes, specify your JOIN
types and your condition is only looking for a single result from p.type
so use =
rather than IN
.
单引号,指定您的JOIN类型,您的条件只是从p.type中查找单个结果,因此使用=而不是IN。
SELECT p.id, m1.value || ' ' || m2.value
FROM places p
INNER JOIN meta m1 ON m1.place = p.id
INNER JOIN meta m2 ON m2.place = p.id
WHERE p.type = '1'
AND m1.key = 'lat'
AND m2.key = 'lng';
#1
0
Single quotes, specify your JOIN
types and your condition is only looking for a single result from p.type
so use =
rather than IN
.
单引号,指定您的JOIN类型,您的条件只是从p.type中查找单个结果,因此使用=而不是IN。
SELECT p.id, m1.value || ' ' || m2.value
FROM places p
INNER JOIN meta m1 ON m1.place = p.id
INNER JOIN meta m2 ON m2.place = p.id
WHERE p.type = '1'
AND m1.key = 'lat'
AND m2.key = 'lng';