Possible Duplicate:
Merge multiple data frames in a list simultaneously可能的重复:在一个列表中同时合并多个数据帧
example data.frames
:
示例data.frames:
df1 = data.frame(id=c('1','73','2','10','43'),v1=c(1,2,3,4,5)) <br>
df2 = data.frame(id=c('7','23','57','2','62','96'),v2=c(1,2,3,4,5,6)) <br>
df3 = data.frame(id=c('23','62'),v3=c(1,2)) <br>
Note: id
is unique for each data.frame. I want the resulting matrix to look like
注意:id对于每个数据都是唯一的。我希望得到的矩阵是这样的
1 1 NA NA
2 3 4 NA
7 NA 1 NA
10 4 NA NA
23 NA 2 1
43 5 NA NA
57 NA 3 NA
62 NA 5 2
73 2 NA NA
96 NA 6 NA
In this case, I only show 3 datasets, I actually have at least 22 of them so at the end I want a matrix of nx(22+1) where n is the number of ids for all 22 datasets.
在这种情况下,我只显示了3个数据集,实际上我至少有22个,所以最后我想要一个n(22+1)的矩阵,其中n是所有22个数据集的id数。
Given 2 datasets, I need to get their ids
in the first column and 2nd and 3rd columns are filled with the values, if there is no value exists, then input NA
instead.
给定2个数据集,我需要在第一列中得到它们的id,第二和第三列中填充了这些值,如果没有值,则输入NA。
1 个解决方案
#1
116
Put them into a list
and use merge
with Reduce
将它们放入列表并使用merge with Reduce
Reduce(function(x, y) merge(x, y, all=TRUE), list(df1, df2, df3))
# id v1 v2 v3
# 1 1 1 NA NA
# 2 10 4 NA NA
# 3 2 3 4 NA
# 4 43 5 NA NA
# 5 73 2 NA NA
# 6 23 NA 2 1
# 7 57 NA 3 NA
# 8 62 NA 5 2
# 9 7 NA 1 NA
# 10 96 NA 6 NA
You can also use this more concise version:
你也可以用这个更简洁的版本:
Reduce(function(...) merge(..., all=TRUE), list(df1, df2, df3))
#1
116
Put them into a list
and use merge
with Reduce
将它们放入列表并使用merge with Reduce
Reduce(function(x, y) merge(x, y, all=TRUE), list(df1, df2, df3))
# id v1 v2 v3
# 1 1 1 NA NA
# 2 10 4 NA NA
# 3 2 3 4 NA
# 4 43 5 NA NA
# 5 73 2 NA NA
# 6 23 NA 2 1
# 7 57 NA 3 NA
# 8 62 NA 5 2
# 9 7 NA 1 NA
# 10 96 NA 6 NA
You can also use this more concise version:
你也可以用这个更简洁的版本:
Reduce(function(...) merge(..., all=TRUE), list(df1, df2, df3))