I have following dataframe and vector:
我有以下数据帧和向量:
ddf = data.frame(a=rep(1,10), b=rep(2,10))
xx = c("c", "d", "e", "f")
How can I new empty columns which are named with items in xx ?
如何使用xx中的项目命名的新空列?
I tried following but it does not work:
我试过以下但它不起作用:
ddf = cbind(ddf, data.frame(xx))
Error in data.frame(..., check.names = FALSE) :
arguments imply differing number of rows: 10, 4
Following also does not work:
以下也不起作用:
for(i in 1:length(xx)){
ddf$(xx[i]) = ""
}
Error: unexpected '(' in:
"for(i in 1:length(xx)){
ddf$("
}
Error: unexpected '}' in "}"
2 个解决方案
#1
23
This will get you there:
这会让你到达那里:
ddf[xx] <- NA
# a b c d e f
#1 1 2 NA NA NA NA
#2 1 2 NA NA NA NA
#3 1 2 NA NA NA NA
#...
You can't directly use something like ddf$xx
because this will try to assign to a column called xx
rather than interpreting xx
. You need to use [
and [<-
functions, using the square brackets when you are dealing with a character string - like ddf["columnname"]
.
你不能直接使用类似ddf $ xx的东西,因为这会尝试分配给一个名为xx的列而不是解释xx。你需要使用[和[< - 函数,在处理字符串时使用方括号 - 比如ddf [“columnname”]。
The reason why it selects columns is because data.frames
are lists essentially:
它选择列的原因是因为data.frames本质上是列表:
is.list(ddf)
#[1] TRUE
as.list(ddf)
#$a
# [1] 1 1 1 1 1 1 1 1 1 1
#
#$b
# [1] 2 2 2 2 2 2 2 2 2 2
...with each column corresponding to a list entry. So if you don't use a comma to specify a row, like ddf["name",]
or a column like ddf[,"name"]
, you get the column by default.
...每列对应一个列表条目。因此,如果您不使用逗号指定行,例如ddf [“name”,]或ddf [,“name”]之类的列,则默认情况下会获得该列。
#2
4
This seems to succeed:
这似乎成功了:
> cbind(ddf, setNames( lapply(xx, function(x) x=NA), xx) )
a b c d e f
1 1 2 NA NA NA NA
2 1 2 NA NA NA NA
3 1 2 NA NA NA NA
4 1 2 NA NA NA NA
5 1 2 NA NA NA NA
6 1 2 NA NA NA NA
7 1 2 NA NA NA NA
8 1 2 NA NA NA NA
9 1 2 NA NA NA NA
10 1 2 NA NA NA NA
#1
23
This will get you there:
这会让你到达那里:
ddf[xx] <- NA
# a b c d e f
#1 1 2 NA NA NA NA
#2 1 2 NA NA NA NA
#3 1 2 NA NA NA NA
#...
You can't directly use something like ddf$xx
because this will try to assign to a column called xx
rather than interpreting xx
. You need to use [
and [<-
functions, using the square brackets when you are dealing with a character string - like ddf["columnname"]
.
你不能直接使用类似ddf $ xx的东西,因为这会尝试分配给一个名为xx的列而不是解释xx。你需要使用[和[< - 函数,在处理字符串时使用方括号 - 比如ddf [“columnname”]。
The reason why it selects columns is because data.frames
are lists essentially:
它选择列的原因是因为data.frames本质上是列表:
is.list(ddf)
#[1] TRUE
as.list(ddf)
#$a
# [1] 1 1 1 1 1 1 1 1 1 1
#
#$b
# [1] 2 2 2 2 2 2 2 2 2 2
...with each column corresponding to a list entry. So if you don't use a comma to specify a row, like ddf["name",]
or a column like ddf[,"name"]
, you get the column by default.
...每列对应一个列表条目。因此,如果您不使用逗号指定行,例如ddf [“name”,]或ddf [,“name”]之类的列,则默认情况下会获得该列。
#2
4
This seems to succeed:
这似乎成功了:
> cbind(ddf, setNames( lapply(xx, function(x) x=NA), xx) )
a b c d e f
1 1 2 NA NA NA NA
2 1 2 NA NA NA NA
3 1 2 NA NA NA NA
4 1 2 NA NA NA NA
5 1 2 NA NA NA NA
6 1 2 NA NA NA NA
7 1 2 NA NA NA NA
8 1 2 NA NA NA NA
9 1 2 NA NA NA NA
10 1 2 NA NA NA NA