How i get max pair in a list of pairs with min y?
我如何在min y的对列表中获得最大对？
I got this list:
我有这个清单：
L =[[1,3],[2,5],[-4,0],[2,1],[0,9]]
With max(L) i get [2,5], but i want [2,1].
使用max（L）我得到[2,5]，但我想要[2,1]。
3 个解决方案
#1
17
max(L, key=lambda item: (item[0], -item[1]))
Output:
输出：
[2, 1]
#2
1
Your request is kind of cryptic, but I think this is what you want:
您的要求有点神秘，但我认为这就是您想要的：
x, y = zip(*L)
maxPairs = [L[i] for i,a in enumerate(x) if a == max(x)]
returnPair = sorted(maxPairs)[0]
#3
0
import operator
get_y= operator.itemgetter(1)
min(L, key=get_y)[0]
Finds the coordinate with minimum y, retrieves x.
找到最小y的坐标，检索x。
If you dislike operator.itemgetter, do:
如果您不喜欢operator.itemgetter，请执行以下操作：
min(L, key=lambda c: c[1])[0]
#1
17
max(L, key=lambda item: (item[0], -item[1]))
Output:
输出：
[2, 1]
#2
1
Your request is kind of cryptic, but I think this is what you want:
您的要求有点神秘，但我认为这就是您想要的：
x, y = zip(*L)
maxPairs = [L[i] for i,a in enumerate(x) if a == max(x)]
returnPair = sorted(maxPairs)[0]
#3
0
import operator
get_y= operator.itemgetter(1)
min(L, key=get_y)[0]
Finds the coordinate with minimum y, retrieves x.
找到最小y的坐标，检索x。
If you dislike operator.itemgetter, do:
如果您不喜欢operator.itemgetter，请执行以下操作：
min(L, key=lambda c: c[1])[0]