What is the equivalent Python/Pandas for the following R commands?
以下R命令的等效Python / Pandas是什么?
matrix1[!matrix2] <- 0
The goal is to compare two matrices, if the elements are different a zero should be assigned.
目标是比较两个矩阵,如果元素不同,则应分配零。
1 个解决方案
#1
1
You can use the DataFrame where method:
您可以使用DataFrame where方法:
In [11]: df1 = pd.DataFrame([[1, 2], [3, 4]])
In [12]: df2 = pd.DataFrame([[1, 2], [3, 5]])
In [13]: df1.where(df1 == df2, 0)
Out[13]:
0 1
0 1 2
1 3 0
to do this inplace (modifying df
):
在这里做这个(修改df):
In [14]: df.where(df==df1, 0, inplace=True)
#1
1
You can use the DataFrame where method:
您可以使用DataFrame where方法:
In [11]: df1 = pd.DataFrame([[1, 2], [3, 4]])
In [12]: df2 = pd.DataFrame([[1, 2], [3, 5]])
In [13]: df1.where(df1 == df2, 0)
Out[13]:
0 1
0 1 2
1 3 0
to do this inplace (modifying df
):
在这里做这个(修改df):
In [14]: df.where(df==df1, 0, inplace=True)