what is the best way to compare int arrays b and c with a:
将int数组b和c与a进行比较的最佳方法是什么?
int a[] = {0,1,0,0,1};
int b[] = {0,1,0,0,1};
int c[] = {1,1,0,0,1};
b and c are just examples, assume they can be any combination of 0s and 1s.
b和c只是示例,假设它们可以是0和1的任意组合。
I am trying to detect arrays identical to a. I have googled this for a while and have not found a satisfactory answer.
我试图检测与a相同的数组。我用谷歌搜索了一段时间,但没有找到满意的答案。
This is a beginners question I realise, thank you for your patience.
这是我意识到的初学者问题,谢谢你的耐心等待。
4 个解决方案
#1
20
Use the standard memcmp
function from <string.h>
.
使用
memcmp(a, b, sizeof(a)) == 0
whenever a
and b
are equal.
每当a和b相等时。
#2
5
If you mean
如果你的意思是
int a[] = {0,1,0,0,1};
int b[] = {0,1,0,0,1};
int c[] = {1,1,0,0,1};
then
然后
memcmp(a, b, sizeof(a)); /* returns zero for a match */
memcmp(a, c, sizeof(a)); /* returns nonzero for no match */
#3
4
Use a loop and compare the individual elements one after another.
使用循环并逐个比较各个元素。
#4
0
More information is needed on the question..! i can divide your question in two ways as below,
有关这个问题需要更多信息..!我可以通过以下两种方式划分你的问题,
- Compare array contents considering order?? Ex:char a[]={a,b,c},b[]={a,c,b} here since u r considering the order,the contents are not same so a!=b
- 比较数组内容考虑顺序?例:char a [] = {a,b,c},b [] = {a,c,b}这里因为你考虑顺序,内容不一样所以a!= b
- compare array contents irrespective of order? Ex:char a[]={a,b,c},b[]={a,c,b} here if u r not considering the order,the contents are same so a==b
- 比较数组内容而不管顺序?例:char a [] = {a,b,c},b [] = {a,c,b}这里如果不考虑订单,内容相同所以a == b
Solution for Question no 1: one can use memcmp for this problem.Because memcomp will compare lexicographical and return 0 or 1 or -1 as below
问题1的解决方案:可以使用memcmp解决此问题。因为memcomp将比较词典并返回0或1或-1,如下所示
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','b','c'};
char b[]={'a','b','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:0***
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','c','b'};
char b[]={'a','b','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:1***
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','b','c'};
char b[]={''b,'a','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:-1***
Solution for Question no 2: one can use memcmp for this problem, the best solution for this problem is as below
问题2的解决方案:可以使用memcmp来解决这个问题,这个问题的最佳解决方案如下
here i answered for the above problem https://*.com/a/36130812/5206646
在这里我回答了上述问题https://*.com/a/36130812/5206646
#1
20
Use the standard memcmp
function from <string.h>
.
使用
memcmp(a, b, sizeof(a)) == 0
whenever a
and b
are equal.
每当a和b相等时。
#2
5
If you mean
如果你的意思是
int a[] = {0,1,0,0,1};
int b[] = {0,1,0,0,1};
int c[] = {1,1,0,0,1};
then
然后
memcmp(a, b, sizeof(a)); /* returns zero for a match */
memcmp(a, c, sizeof(a)); /* returns nonzero for no match */
#3
4
Use a loop and compare the individual elements one after another.
使用循环并逐个比较各个元素。
#4
0
More information is needed on the question..! i can divide your question in two ways as below,
有关这个问题需要更多信息..!我可以通过以下两种方式划分你的问题,
- Compare array contents considering order?? Ex:char a[]={a,b,c},b[]={a,c,b} here since u r considering the order,the contents are not same so a!=b
- 比较数组内容考虑顺序?例:char a [] = {a,b,c},b [] = {a,c,b}这里因为你考虑顺序,内容不一样所以a!= b
- compare array contents irrespective of order? Ex:char a[]={a,b,c},b[]={a,c,b} here if u r not considering the order,the contents are same so a==b
- 比较数组内容而不管顺序?例:char a [] = {a,b,c},b [] = {a,c,b}这里如果不考虑订单,内容相同所以a == b
Solution for Question no 1: one can use memcmp for this problem.Because memcomp will compare lexicographical and return 0 or 1 or -1 as below
问题1的解决方案:可以使用memcmp解决此问题。因为memcomp将比较词典并返回0或1或-1,如下所示
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','b','c'};
char b[]={'a','b','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:0***
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','c','b'};
char b[]={'a','b','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:1***
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','b','c'};
char b[]={''b,'a','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:-1***
Solution for Question no 2: one can use memcmp for this problem, the best solution for this problem is as below
问题2的解决方案:可以使用memcmp来解决这个问题,这个问题的最佳解决方案如下
here i answered for the above problem https://*.com/a/36130812/5206646
在这里我回答了上述问题https://*.com/a/36130812/5206646