如果条件，Ant正则表达式比较

I have str1="A sample string". If the str1 contains sample, I need to echo something like match and otherwise not matching. I am not familiar with ant scripts. Please help me.

我有str1 =“一个示例字符串”。如果str1包含样本，我需要回显匹配之类的东西，否则不匹配。我不熟悉ant脚本。请帮帮我。

2 个解决方案

#1

If you are using newer ant, try... http://ant.apache.org/manual/Tasks/conditions.html

如果您使用较新的蚂蚁，请尝试... http://ant.apache.org/manual/Tasks/conditions.html

<condition property="legal-password">
  <matches pattern="[1-9]" string="${user-input}"/>
</condition>
<fail message="Your password should at least contain one number"
      unless="legal-password"/>

#2

If you just want to know if a substring exists in the string, you can use <contains> task together with <if> task from ant-contrib. If you want to scan for a pattern (a regexp) in a string, use <matches> instead of <contains>.

如果您只想知道字符串中是否存在子字符串，则可以将任务与ant-contrib中的任务一起使用。如果要扫描字符串中的模式（正则表达式），请使用而不是。

Check for examples in this page: Ant Manual: Condition Tasks

检查此页面中的示例：Ant手册：条件任务

Also, a example:

还有一个例子：

<if>
    <contains string="a sample string" substring="sample" />
    <then>
        <echo>match</echo>
    </then>
    <else>
        <echo>not match</echo>
    </else>
</if>

#1