集合,set(),记住:
1个特点:去重,把列表变成集合,达到自动去重操作,无序
5个关系:测试两个列表的交差并子反向差集
方法:
- | add(...) 常用,已存在元素去重不生效
- | Add an element to a set.
- | This has no effect if the element is already present.
>>> list1=[3,2,1,1,2,3,4,5]
View Code
>>> set(list1)
{1, 2, 3, 4, 5}
>>> list2=[3,4,5,6,7,8]
>>> set(list1).add(2)
>>> set(list1).add(6)
>>> print(set(list1).add(2))
None
>>> print(set(list1).add(6))
None
>>> set1=set(list1)
>>> set2=set(list2)
>>> set1,set2
({1, 2, 3, 4, 5}, {3, 4, 5, 6, 7, 8})
>>> set1.add(3)
>>> print(set1.add(3)
... )
None
>>> print(set1.add(7))
None
>>> set1.add('aaa')
>>> set1
{1, 2, 3, 4, 5, 7, 'aaa'}
>>> id(set1)
140138768484616
>>> set1.add('aaaa')
>>> id(set1)
140138768484616
>>> set1
{1, 2, 3, 4, 5, 7, 'aaa', 'aaaa'}
>>> set1.add('7')
>>> set1
{1, 2, 3, 4, 5, 7, 'aaa', 'aaaa', '7'}
>>> set1.add(7)
>>> set1
{1, 2, 3, 4, 5, 7, 'aaa', 'aaaa', '7'} - 如果是字符串,则拆分成单个字符集合
-
>>> set('abc')
{'a', 'c', 'b'}
- | clear(...) 清空一个集合
- | Remove all elements from this set.
>>> set1.clear()
>>> set1
set() - | copy(...) 影子复制,指向同一个内存地址
- | Return a shallow copy of a set. |
>>> list1
[3, 2, 1, 1, 2, 3, 4, 5]
>>> list2
[3, 4, 5, 6, 7, 8]
>>> set1=set(list1)>>> id(set1)
140138768485512>>> set3=set1.copy()
>>> id(set3)
140138695576712 - | difference(...) 差集,格式set1.difference(set2),求in list1 not in list2的集合
- | Return the difference of two or more sets as a new set. |
- | (i.e. all elements that are in this set but not the others.)
>>> set1
{1, 2, 3, 4, 5}
>>> set2
{3, 4, 5, 6, 7, 8}
>>> set1.difference(set2)
{1, 2} - | difference_update(...) 删除在本集合同时也在其他集合的元素,差集
- | Remove all elements of another set from this set. |
>>> set1=set(list1)
>>> set2=set(list2)
>>> set1,set2
({1, 2, 3, 4, 5}, {3, 4, 5, 6, 7, 8})
>>> set1=set(list1)>>> set2=set(list2)
>>> set2.difference_update(set1)
>>> set2
{6, 7, 8} - | discard(...) 删除一个在本集合中的元素
- | Remove an element from a set if it is a member.
- |
- | If the element is not a member, do nothing. |
>>> set3=set([1,2,3,'a','b','c'])
>>> set3.discard(1)
>>> set3
{2, 3, 'c', 'b', 'a'}
>>> set3.discard('a')
>>> set3
{2, 3, 'c', 'b'}
>>> set3.discard('dd')
>>> set3
{2, 3, 'c', 'b'} - | intersection(...)并集,同时在两个集合中的元素
- | Return the intersection of two sets as a new set.
- |
- | (i.e. all elements that are in both sets.) |
>>> set1
{1, 2, 3, 4, 5}
>>> set2
{3, 4, 5, 6, 7, 8}
>>> set1.intersection(set2)
{3, 4, 5}
>>> set2.intersection(set1)
{3, 4, 5} - | intersection_update(...) 交集
- | Update a set with the intersection of itself and another. |
>>> set1,set2
({1, 2, 3, 4, 5}, {3, 4, 5, 6, 7, 8})
>>> set1.intersection_update(set2)
>>> set1
{3, 4, 5} - | isdisjoint(...) 返回布尔值,判断两个集合是否没有并集
- | Return True if two sets have a null intersection.
- |
>>> set1,set2,set3,set4
({3, 4, 5}, {3, 4, 5, 6, 7, 8}, {2, 3, 'c', 'b'}, {'y', 'x', 'z'})
>>> set1.isdisjoint(set2)
False
>>> set1.isdisjoint(set4)
True - | issubset(...) 返回布尔值,判断前一个集合是否是后一个集合的子集
- | Report whether another set contains this set. |
>>> set1
{3, 4, 5}
>>> set5
{3, 4}
>>> set5.issubset(set1)
True - | issuperset(...) 返回布尔值,判断前一个集合是否是后一个集合的父集
- | Report whether this set contains another set. |
>>> set1
{3, 4, 5}
>>> set5
{3, 4}
>>> set1.issuperset(set5)
True - | pop(...) 随机删除一个集合元素,返回被删除元素,空集合删除则报错
- | Remove and return an arbitrary set element.
- | Raises KeyError if the set is empty. |
>>> set1
{3, 4, 5}
>>> set1.pop()
3
>>> set1
{4, 5}
>>> set1.pop()
4
>>> set1.pop()
5
>>> set1.pop()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyError: 'pop from an empty set' - | remove(...) 删除指定在集合中的元素
- | Remove an element from a set; it must be a member. |
>>> set1=set(list1)
>>> set1
{1, 2, 3, 4, 5}
>>> set1.remove(1)
>>> set1
{2, 3, 4, 5}
>>> set1.remove('a')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyError: 'a' - | symmetric_difference(...) 对称差集,集合A与集合B不相交的部分,交集的反集
- | Return the symmetric difference of two sets as a new set.
- | (i.e. all elements that are in exactly one of the sets.)
>>> set1
{1, 2, 3, 4, 5}
>>> set6={4,5,6,7,8}
>>> set1.symmetric_difference(set6)
{1, 2, 3, 6, 7, 8}
>>> set6.symmetric_difference(set1)
{1, 2, 3, 6, 7, 8}
>>> set1,set7
({1, 2, 3, 4, 5}, {'a', 'c', 'b'})
>>> set1.symmetric_difference(set7)
{'c', 2, 3, 1, 4, 5, 'b', 'a'}
- | symmetric_difference_update(...)
- | Update a set with the symmetric difference of itself and another.
- |
- | union(...) 并集
- | Return the union of sets as a new set.
- | (i.e. all elements that are in either set.)
>>> set1
{1, 2, 3, 4, 5}
>>> set2
{3, 4, 5, 6, 7, 8}
>>> set1.union(set2)
{1, 2, 3, 4, 5, 6, 7, 8}
- | update(...) 用交集更新到set1的集合
- | Update a set with the union of itself and others. |
>>> set1
{1, 2, 3, 4, 5}
>>> set2
{3, 4, 5, 6, 7, 8}
>>> set1.update(set2)
>>> set1
{1, 2, 3, 4, 5, 6, 7, 8}
>>>