I was looking for some standard PHP function to replace some value of an array with other, but surprisingly I haven't found any, so I have to write my own:
我正在寻找一些标准的PHP函数来替换其他的数组值,但令人惊讶的是我没有找到任何,所以我必须自己编写:
function array_replace_value(&$ar, $value, $replacement)
{
if (($key = array_search($ar, $value)) !== FALSE) {
$ar[$key] = $replacement;
}
}
But I still wonder - for such an easy thing there must already be some function for it! Or maybe much easier solution than this one invented by me?
但我仍然想知道 - 对于这么简单的事情,它必须已经有了一些功能!或者可能比我发明的更容易解决方案?
Note that this function will only do one replacement. I'm looking for existing solutions that similarly replace a single occurrence, as well as those that replace all occurrences.
请注意,此功能仅执行一次替换。我正在寻找类似替换单个事件的现有解决方案,以及替换所有事件的解决方案。
8 个解决方案
#1
19
While there isn't one function equivalent to the sample code, you can use array_keys
(with the optional search value parameter), array_fill
and array_replace
to achieve the same thing:
虽然没有一个函数等效于示例代码,但您可以使用array_keys(使用可选的搜索值参数),array_fill和array_replace来实现相同的功能:
EDIT by Tomas: the code was not working, corrected it:
由Tomas编辑:代码无效,纠正了它:
$ar = array_replace($ar,
array_fill_keys(
array_keys($ar, $value),
$replacement
)
);
#2
22
Instead of a function that only replaces occurrences of one value in an array, there's the more general array_map
:
而不是仅替换数组中一个值的出现的函数,而是更通用的array_map:
array_map(function ($v) use ($value, $replacement) {
return $v == $value ? $replacement : $v;
}, $arr);
To replace multiple occurrences of multiple values using array of value => replacement:
要使用value => replacement数组替换多个值的多次出现:
array_map(function ($v) use ($replacement) {
return isset($replacement[$v]) ? $replacement[$v] : $v;
}, $arr);
To replace a single occurrence of one value, you'd use array_search
as you do. Because the implementation is so short, there isn't much reason for the PHP developers to create a standard function to perform the task. Not to say that it doesn't make sense for you to create such a function, if you find yourself needing it often.
要替换单个值的一个值,您可以像使用array_search一样。由于实现很短,因此PHP开发人员没有太多理由创建标准函数来执行任务。如果您发现自己经常需要它,那并不是说创建这样的函数没有意义。
#3
5
Try this function.
试试这个功能。
public function recursive_array_replace ($find, $replace, $array) {
if (!is_array($array)) {
return str_replace($find, $replace, $array);
}
$newArray = [];
foreach ($array as $key => $value) {
$newArray[$key] = recursive_array_replace($find, $replace, $value);
}
return $newArray;
}
Cheers!
干杯!
#4
3
If performance is an issue, one may consider not to create multiple functions within array_map()
. Note that isset()
is extremely fast, and this solutions does not call any other functions at all.
如果性能是个问题,可以考虑不在array_map()中创建多个函数。请注意,isset()非常快,此解决方案根本不会调用任何其他函数。
$replacements = array(
'search1' => 'replace1',
'search2' => 'replace2',
'search3' => 'replace3'
);
foreach ($a as $key => $value) {
if (isset($replacements[$value])) {
$a[$key] = $replacements[$value];
}
}
#5
2
What about array_walk()
with callback?
带回调的array_walk()怎么样?
$array = ['*pasta', 'cola', 'pizza'];
$search = '*';
$replace = '\*';
array_walk($array,
function (&$v) use ($search, $replace){
$v = str_replace($search, $replace, $v);
}
);
print_r($array);
#6
0
Based on Deept Raghav
's answer, I created the follow solution that does regular expression search.
根据Deept Raghav的回答,我创建了以下解决方案,进行正则表达式搜索。
$arr = [
'Array Element 1',
'Array Element 2',
'Replace Me',
'Array Element 4',
];
$arr = array_replace(
$arr,
array_fill_keys(
array_keys(
preg_grep('/^Replace/', $arr)
),
'Array Element 3'
)
);
echo '<pre>', var_export($arr), '</pre>';
PhpFiddle: http://phpfiddle.org/lite/code/un7u-j1pt
PhpFiddle:http://phpfiddle.org/lite/code/un7u-j1pt
#7
0
Depending whether it's the value, the key or both you want to find and replace on you could do something like this:
根据您要查找和替换的值,键或两者,您可以执行以下操作:
$array = json_decode( str_replace( $replace, $with, json_encode( $array ) ), true );
I'm not saying this is the most efficient or elegant, but nice and simple.
我不是说这是最有效或最优雅,但又好又简单。
#8
-1
<b>$green_key = array_search('green', $input); // returns the first key whose value is 'green'
$input[$green_key] = 'apple'; // replace 'green' with 'apple'
$ input [$ green_key] ='apple'; //用'apple'替换'green'
#1
19
While there isn't one function equivalent to the sample code, you can use array_keys
(with the optional search value parameter), array_fill
and array_replace
to achieve the same thing:
虽然没有一个函数等效于示例代码,但您可以使用array_keys(使用可选的搜索值参数),array_fill和array_replace来实现相同的功能:
EDIT by Tomas: the code was not working, corrected it:
由Tomas编辑:代码无效,纠正了它:
$ar = array_replace($ar,
array_fill_keys(
array_keys($ar, $value),
$replacement
)
);
#2
22
Instead of a function that only replaces occurrences of one value in an array, there's the more general array_map
:
而不是仅替换数组中一个值的出现的函数,而是更通用的array_map:
array_map(function ($v) use ($value, $replacement) {
return $v == $value ? $replacement : $v;
}, $arr);
To replace multiple occurrences of multiple values using array of value => replacement:
要使用value => replacement数组替换多个值的多次出现:
array_map(function ($v) use ($replacement) {
return isset($replacement[$v]) ? $replacement[$v] : $v;
}, $arr);
To replace a single occurrence of one value, you'd use array_search
as you do. Because the implementation is so short, there isn't much reason for the PHP developers to create a standard function to perform the task. Not to say that it doesn't make sense for you to create such a function, if you find yourself needing it often.
要替换单个值的一个值,您可以像使用array_search一样。由于实现很短,因此PHP开发人员没有太多理由创建标准函数来执行任务。如果您发现自己经常需要它,那并不是说创建这样的函数没有意义。
#3
5
Try this function.
试试这个功能。
public function recursive_array_replace ($find, $replace, $array) {
if (!is_array($array)) {
return str_replace($find, $replace, $array);
}
$newArray = [];
foreach ($array as $key => $value) {
$newArray[$key] = recursive_array_replace($find, $replace, $value);
}
return $newArray;
}
Cheers!
干杯!
#4
3
If performance is an issue, one may consider not to create multiple functions within array_map()
. Note that isset()
is extremely fast, and this solutions does not call any other functions at all.
如果性能是个问题,可以考虑不在array_map()中创建多个函数。请注意,isset()非常快,此解决方案根本不会调用任何其他函数。
$replacements = array(
'search1' => 'replace1',
'search2' => 'replace2',
'search3' => 'replace3'
);
foreach ($a as $key => $value) {
if (isset($replacements[$value])) {
$a[$key] = $replacements[$value];
}
}
#5
2
What about array_walk()
with callback?
带回调的array_walk()怎么样?
$array = ['*pasta', 'cola', 'pizza'];
$search = '*';
$replace = '\*';
array_walk($array,
function (&$v) use ($search, $replace){
$v = str_replace($search, $replace, $v);
}
);
print_r($array);
#6
0
Based on Deept Raghav
's answer, I created the follow solution that does regular expression search.
根据Deept Raghav的回答,我创建了以下解决方案,进行正则表达式搜索。
$arr = [
'Array Element 1',
'Array Element 2',
'Replace Me',
'Array Element 4',
];
$arr = array_replace(
$arr,
array_fill_keys(
array_keys(
preg_grep('/^Replace/', $arr)
),
'Array Element 3'
)
);
echo '<pre>', var_export($arr), '</pre>';
PhpFiddle: http://phpfiddle.org/lite/code/un7u-j1pt
PhpFiddle:http://phpfiddle.org/lite/code/un7u-j1pt
#7
0
Depending whether it's the value, the key or both you want to find and replace on you could do something like this:
根据您要查找和替换的值,键或两者,您可以执行以下操作:
$array = json_decode( str_replace( $replace, $with, json_encode( $array ) ), true );
I'm not saying this is the most efficient or elegant, but nice and simple.
我不是说这是最有效或最优雅,但又好又简单。
#8
-1
<b>$green_key = array_search('green', $input); // returns the first key whose value is 'green'
$input[$green_key] = 'apple'; // replace 'green' with 'apple'
$ input [$ green_key] ='apple'; //用'apple'替换'green'