从键/值对的数组中获取信息

I have the following snippet of code that is creating the following array...

我有以下代码片段创建以下数组...

while ($stmt->fetch()) {
  foreach($row as $key => $val) {
    $x[$key] = $val;
  }
  $results[] = $x;
}

Results in the follow array:

结果如下:

Array ( [0] => Array ( [cap_login] => master [cap_pword] => B-a411dc195b1f04e638565e5479b1880956011badb73361ca ) )

Basically I want to extract the cap_login and cap_pword values for testing. For some reason I can't get it! I've tried this kind of thing:

基本上我想提取cap_login和cap_pword值以进行测试。出于某种原因,我无法得到它!我试过这种事:

echo $results[$cap_login];

but I get the error

但我得到了错误

Undefined variable: cap_login

Can someone put me right here? Thanks.

有人能把我放在这儿吗?谢谢。

2 个解决方案

#1

cap_login is in an array within $results so you would have to do $results[0]['cap_login']

cap_login在$ results中的数组中,所以你必须做$ results [0] ['cap_login']

#2

You would have to do the following:

您必须执行以下操作:

echo $x[0]['cap_login'] . '<br />';
echo $x[0]['cap_pword'];

The reson $results[$cap_login] wont work is because there isn't a variable called $cap_login, there is a string called cap login. In addition, there isn't a key in $results called $cap_login. There is a value in $results called 'cap_login'

共振$ results [$ cap_login]无法工作是因为没有名为$ cap_login的变量,有一个名为cap login的字符串。另外,$ result_login中的$ result中没有关键字。 $ result中有一个名为'cap_login'的值

#1