When I check value of an array using var_dump() function.
当我使用var_dump()函数检查数组的值时。
var_dump($data['content']);
I have result
我有结果
array(1) { [0]=> array(10) { ["IDUser"]=> string(1) "1" ["Name"]=> string(5) "admin" ["Password"]=> string(32) "44ca5fa5c67e434b9e779c5febc46f06" ["Fullname"]=> string(18) "Nguyễn Tá Lợi" ["Gender"]=> string(1) "0" ["Birthday"]=> string(10) "0000-00-00" ["Address"]=> string(0) "" ["Email"]=> string(0) "" ["PhoneNumber"]=> string(0) "" ["Status"]=> string(1) "1" } }
I want get value with key ["Name"] so I use $data['content']['Name']
but it's incorrect
How to get value of "Name" in this array?
我想要使用key ["Name"]获取值,所以我使用$data['content']['Name'],但是如何在这个数组中获取"Name"的值是不正确的?
2 个解决方案
#1
3
$data['content'][0]['Name']
should do it
$ data[0](“内容”)(“名字”)应该做它
#2
2
Value of Name
is available on 0 index of content
so you can not get the Name value as:
名称的值在内容索引为0时可用,因此不能得到名称的值为:
$data['content']['Name']
You need to get Name as:
您需要获得名称为:
$data['content'][0]['Name'] // add 0 index of content.
#1
3
$data['content'][0]['Name']
should do it
$ data[0](“内容”)(“名字”)应该做它
#2
2
Value of Name
is available on 0 index of content
so you can not get the Name value as:
名称的值在内容索引为0时可用,因此不能得到名称的值为:
$data['content']['Name']
You need to get Name as:
您需要获得名称为:
$data['content'][0]['Name'] // add 0 index of content.