As far as I understand the following line of code should split a string at new lines (\r
, \n
and \r\n
).
据我所知,下面一行代码应该在新行(\r, \n和\r\n)上分割一个字符串。
preg_split("%\R%", $str);
Why is it that
为什么
var_dump(preg_split("%\R%", "Å"));
outputs
输出
array(2) {
[0]=>
string(1) "▒"
[1]=>
string(0) ""
}
but
但
var_dump(preg_split("%(\r|\n|\r\n)%", "Å"));
works as expected and does not split the character? I know that I should use the "u" modifier (PCRE_UTF8) because the character is in UTF-8 but why does preg_split
think that Å (0xC3 0x85
) could contain a new line?
按预期工作,不分裂人物?我知道我应该使用“u”修饰符(PCRE_UTF8),因为字符在UTF-8中,但是为什么preg_split认为A (0xC3 0x85)可以包含一个新的行呢?
1 个解决方案
#1
3
You have also mentioned that Å
is 0xC3 0x85
您还提到了A是0xC3 0x85。
As per this PCRE documentation without using u
modifier \R
is equivalent of this atomic group:
根据此PCRE文档,不使用u修改器\R等同于这个原子组:
(?>\r\n|\n|\r|\f|\x0b|\x85)
Note presence of \x85
in both sets.
注意两组中都有\x85。
Hence split on \R
without using u
modifier gives one extra element in output array since it is able to split on \x85
giving you just \xC3
and an empty result in resulting array.
因此,在不使用u修改器的情况下在\R上拆分,会在输出数组中提供一个额外的元素,因为它可以在\x85上拆分,只会产生\xC3和结果为空的数组。
#1
3
You have also mentioned that Å
is 0xC3 0x85
您还提到了A是0xC3 0x85。
As per this PCRE documentation without using u
modifier \R
is equivalent of this atomic group:
根据此PCRE文档,不使用u修改器\R等同于这个原子组:
(?>\r\n|\n|\r|\f|\x0b|\x85)
Note presence of \x85
in both sets.
注意两组中都有\x85。
Hence split on \R
without using u
modifier gives one extra element in output array since it is able to split on \x85
giving you just \xC3
and an empty result in resulting array.
因此,在不使用u修改器的情况下在\R上拆分,会在输出数组中提供一个额外的元素,因为它可以在\x85上拆分,只会产生\xC3和结果为空的数组。