PHP preg_split忽略转义序列

How can I split string one by one but ignoring escaped character ? Here my example, I have string :-

如何逐个拆分字符串但忽略转义字符?这是我的例子,我有字符串: -

\ntest\rtest\n

I want it to be like this :-

我希望它是这样的: -

Array
(
    [0] => \n
    [1] => t
    [2] => e
    [3] => s
    [4] => t
    [5] => \r
    [6] => t
    [7] => e
    [8] => s
    [9] => t
    [10] => \n
)

Someone said use preg_split, but i don't know much about regex.

有人说使用preg_split,但我不太了解正则表达式。

4 个解决方案

#1

Backslashes need escaping in RegEx.
When referencing one actual backslash you'll need a series of three \\\

反斜杠需要在RegEx中转义。当引用一个实际反斜杠时,你需要一系列三个\\\

RegEx match

preg_match_all("/\\\?[^\\\]/", $str, $matches);

Live demo code: http://codepad.viper-7.com/FLjH9A

现场演示代码:http://codepad.viper-7.com/FLjH9A

RegEx split - just for educational purposes, as match is more appropriate in this case

RegEx拆分 - 仅用于教育目的,因为在这种情况下匹配更合适

$matches=preg_split("/(?<=\\\[^\\\])(?!$)|(?<=[^\\\])(?!$)/", $str);

Live demo code: http://codepad.viper-7.com/yrbtMV

现场演示代码:http://codepad.viper-7.com/yrbtMV

#2

You can remove the escaped characters of choice first and then apply str_split():

您可以先删除所选的转义字符,然后应用str_split():

$str = "\ntest\rtest\n";

print_r(str_split(strtr($str, array(
    '\r' => '', 
    '\n' => '',
))));

#3

if you only want to get the array, you can read the string with char one by one. no matter about regex.

如果你只想获取数组,你可以逐个读取字符串。无论是关于正则表达式。

#4

If you want to match each single character (optionally preceded by a \), you can use:

如果要匹配每个单个字符(可选地以\开头),您可以使用:

$str = '\ntest\rtest\n';
preg_match_all('/\\\?[a-zA-Z]/', $str, $matches);

Which would return an array with both the single and escaped character sequences.

哪个会返回包含单个和转义字符序列的数组。

#1