explode on empty string returns array count as 1.
在空字符串上爆炸会将数组计数返回为1。
$consName =explode("|",$docDet['doc_cons_filename']);
count($consName);
If there is some value in $docDet['doc_cons_filename'] like ab|cd|de then count($consName) returns 3.
如果$ docDet ['doc_cons_filename']中有一些值,如ab | cd | de则count($ consName)返回3。
But its returning 1 if $docDet['doc_cons_filename'] has empty value.
但是如果$ docDet ['doc_cons_filename']的值为空,则返回1。
is it possible to return count as 0 if we perform count(explode("|",$docDet['doc_cons_filename'])) where $docDet['doc_cons_filename'] = ""
如果我们执行count,则可以将count返回为0(explode(“|”,$ docDet ['doc_cons_filename']))其中$ docDet ['doc_cons_filename'] =“”
Can anyone help me with solution?
任何人都可以帮我解决问题吗?
2 个解决方案
#1
-3
$arr = array();
$str = "yes you are!";
if($i = substr_count($str,"|"))
$arr = explode("|", $str, $i+1);
echo count($arr);
#2
5
The solution would be to count explicitly how many times separator is found within your string. See substr_count()
解决方案是明确计算字符串中找到分隔符的次数。请参阅substr_count()
#1
-3
$arr = array();
$str = "yes you are!";
if($i = substr_count($str,"|"))
$arr = explode("|", $str, $i+1);
echo count($arr);
#2
5
The solution would be to count explicitly how many times separator is found within your string. See substr_count()
解决方案是明确计算字符串中找到分隔符的次数。请参阅substr_count()