为什么我不能立即访问爆炸的数组元素？

Why can't I immediately access elements in the array returned by explode()?

为什么我不能立即访问explode（）返回的数组中的元素？

For example, this doesn't work:

例如，这不起作用：

$username = explode('.',$thread_user)[1]; 
//Parse error: syntax error, unexpected '[

But this code does:

但是这段代码确实：

$username = explode('.',$thread_user); 
$username = $username[1];

I don't usually program in PHP, so this is rather confusing to me.

我通常不用PHP编程，所以这对我来说相当混乱。

6 个解决方案

#1

Actually, PHP simply does not support this syntax. In languages like Javascript (for instance), the parser can handle more complex nesting/chaining operations, but PHP is not one of those languages.

实际上，PHP根本不支持这种语法。在像Javascript（例如）这样的语言中，解析器可以处理更复杂的嵌套/链接操作，但PHP不是这些语言之一。

#2

The reason it isn't obvious how to do what you want is that explode could return false. You should check the return value before indexing into it.

不明显如何做你想做的事情的原因是爆炸可能会返回错误。您应该在索引之前检查返回值。

#3

It's version dependent. PHP 5.4 does support accessing the returned array.

它取决于版本。 PHP 5.4支持访问返回的数组。

Source: http://php.net/manual/en/language.types.array.php#example-115

资料来源：http：//php.net/manual/en/language.types.array.php#example-115

#4

Since explode() returns an array, you may use other functions such as $username = current(explode('.',$thread_user));

由于explode（）返回一个数组，你可以使用其他函数，如$ username = current（explode（'。'，$ thread_user））;

#5

I just use my own function:

我只是使用自己的功能：

function explodeAndReturnIndex($delimiter, $string, $index){
    $tempArray = explode($delimiter, $string);
    return $tempArray[$index];
}

the code for your example would then be:

您的示例的代码将是：

$username = explodeAndReturnIndex('.', $thread_user, 1);

#6

Here's how to get it down to one line:

以下是如何将其归结为一行：

$username = current(array_slice(explode('.',$thread_user), indx,1));

$ username = current（array_slice（explode（'。'，$ thread_user），indx，1））;

Where indx is the index you want from the exploded array. I'm new to php but I like saying exploded array :)

其中indx是您想要从爆炸数组中获得的索引。我是php新手，但我喜欢说爆炸阵列:)

#1