播放/ Scala JSON格式

时间:2021-02-28 22:00:53

I have a value class that accepts an Either, which I would like to generate a Play for Scala v2.5.6 JSON Format for:

我有一个值类接受一个Either,我想生成一个Play for Scala v2.5.6 JSON格式:

import org.joda.time.{DateTime, Duration}

case class When(when: Either[DateTime, Duration]) extends AnyVal

I think I have the writes method figured out; the problems I am having are with the reads method. I've attempted two approaches, both failed for different reasons.

我想我已经找到了写法;我遇到的问题是read方法。我尝试了两种方法,都因为不同的原因而失败。

Attempt #1, showing both the reads and writes methods:

尝试#1,显示读写方法:

import play.api.libs.json._
import play.api.libs.json.Json.obj

object When {    
  def apply(dateTime: DateTime): When = When(Left(dateTime))

  def apply(duration: Duration): When = When(Right(duration))

  implicit val whenFormat = new Format[When] {
    def reads(json: JsValue): JsResult[When] = {
      val reads = (__ \ "dateTime").read[Long] { (millis: Long) =>
        When(Left(new DateTime(millis)))
      } | (__ \ "duration").read[Long] { (millis: Long) =>
        When(Right(new Duration(millis)))
      }
      reads.reads(json)
    }

    def writes(o: When): JsValue = obj(
      o.when.fold(
        duration => "duration" -> duration.getMillis,
        dateTime => "dateTime" -> dateTime.getMillis
      )
    )
  }
}

The error messages are:

错误消息是:

overloaded method value read with alternatives:
[error]   (t: Long)play.api.libs.json.Reads[Long] <and>
[error]   (implicit r: play.api.libs.json.Reads[Long])play.api.libs.json.Reads[Long]
[error]  cannot be applied to (Long => When)
[error]       val reads = (__ \ "dateTime").read[Long] { (millis: Long) =>

[error] overloaded method value read with alternatives:
[error]   (t: Long)play.api.libs.json.Reads[Long] <and>
[error]   (implicit r: play.api.libs.json.Reads[Long])play.api.libs.json.Reads[Long]
[error]  cannot be applied to (Long => When)
[error]       } | (__ \ "duration").read[Long] { (millis: Long) =>

Attempt #2, just showing the reads method:

尝试#2,只显示读取方法:

def reads(json: JsValue): JsResult[When] =
  JsSuccess(
    When(Left(new DateTime((__ \ "dateTime").read[Long]))) ||
    When(Right(new Duration((__ \ "duration").read[Long])))
  )

The error message is:

错误消息是:

value || is not a member of When
[error]  Note: implicit value whenFormat is not applicable here because it comes after the application point and it lacks an explicit result type
[error] Error occurred in an application involving default arguments.

I'd just like something that works, and I don't care what approach is used (even one I did not show), so long as it is maintainable and efficient. It would also be helpful to know what was wrong with each of these approaches.

我只是喜欢有用的东西,我不关心使用什么方法(即使是我没有展示的方法),只要它是可维护和有效的。知道每种方法的错误也会有所帮助。

1 个解决方案

#1


7  

Here is working example of how to do this:

以下是如何执行此操作的工作示例:

import org.joda.time.{DateTime, Duration}
import play.api.libs.functional.syntax._
import play.api.libs.json.Reads._
import play.api.libs.json._

object When {
  def apply(dateTime: DateTime): When = When(Left(dateTime))

  def apply(duration: Duration): When = When(Right(duration))

  val reads: Reads[When] = 
    (__ \ "dateTime").read[Long].map(millis => When(Left(new DateTime(millis)))) |
    (__ \ "duration").read[Long].map(millis => When(Right(new Duration(millis))))

  val writes: Writes[When] = new Writes[When] {
    override def writes(o: When): JsValue = Json.obj(
      o.when.fold(
        duration => "duration" -> duration.getMillis,
        dateTime => "dateTime" -> dateTime.getMillis
      )
    )
  }

  implicit val format = Format(reads, writes)
}

basically you should map the reads

基本上你应该映射读数

(__ \ "dateTime").read[Long]

gives you Reads[Long], then you can map result to When. You were just passing parameter. This parameter could be a Long, to just ignore what is read and return that value, or implicit reads for long that you probably don't want to change and should let it stay implicit.

给你Read [Long],然后你可以把结果映射到When。你只是传递参数。这个参数可以是Long,只是忽略读取的内容并返回该值,或者长时间隐式读取,你可能不想改变它应该让它保持隐含。

So then in similar way you can create another reads for duration and combine them with alternative (|) and done, you have reads.

那么以类似的方式你可以创建另一个读取持续时间并将它们与替代(|)组合完成,你有读取。

Your second approach makes no sense. Either use reads and compose them or just manually check if something is there and if not return a different result, but it is not worth doing this, just go with default approach.

你的第二种方法毫无意义。要么使用读取和组合它们,要么只是手动检查是否有东西,如果没有返回不同的结果,但是不值得这样做,只需采用默认方法。

#1


7  

Here is working example of how to do this:

以下是如何执行此操作的工作示例:

import org.joda.time.{DateTime, Duration}
import play.api.libs.functional.syntax._
import play.api.libs.json.Reads._
import play.api.libs.json._

object When {
  def apply(dateTime: DateTime): When = When(Left(dateTime))

  def apply(duration: Duration): When = When(Right(duration))

  val reads: Reads[When] = 
    (__ \ "dateTime").read[Long].map(millis => When(Left(new DateTime(millis)))) |
    (__ \ "duration").read[Long].map(millis => When(Right(new Duration(millis))))

  val writes: Writes[When] = new Writes[When] {
    override def writes(o: When): JsValue = Json.obj(
      o.when.fold(
        duration => "duration" -> duration.getMillis,
        dateTime => "dateTime" -> dateTime.getMillis
      )
    )
  }

  implicit val format = Format(reads, writes)
}

basically you should map the reads

基本上你应该映射读数

(__ \ "dateTime").read[Long]

gives you Reads[Long], then you can map result to When. You were just passing parameter. This parameter could be a Long, to just ignore what is read and return that value, or implicit reads for long that you probably don't want to change and should let it stay implicit.

给你Read [Long],然后你可以把结果映射到When。你只是传递参数。这个参数可以是Long,只是忽略读取的内容并返回该值,或者长时间隐式读取,你可能不想改变它应该让它保持隐含。

So then in similar way you can create another reads for duration and combine them with alternative (|) and done, you have reads.

那么以类似的方式你可以创建另一个读取持续时间并将它们与替代(|)组合完成,你有读取。

Your second approach makes no sense. Either use reads and compose them or just manually check if something is there and if not return a different result, but it is not worth doing this, just go with default approach.

你的第二种方法毫无意义。要么使用读取和组合它们,要么只是手动检查是否有东西,如果没有返回不同的结果,但是不值得这样做,只需采用默认方法。