正在寻找一个正则表达式 - 8个char min w / 1 num和1个char

I'm looking for some help creating a regex that requires 8 char (at a minimum) along w/ 1 number and 1 char (not special char).

我正在寻找一些帮助创建一个正则表达式,需要8个字符(至少)w / 1数字和1个字符(不是特殊字符)。

example: a1234567 is valid but 12345678 is not

示例:a1234567有效但12345678不有效

Any help for a regex newb?

有关正则表达式newb的任何帮助吗?

EDIT:

Thanks for the quick replies- the implementation that worked in VB is shown below

感谢快速回复 - VB中的实现如下所示

Dim ValidPassword As Boolean = Regex.IsMatch(Password, "^(?=.*[0-9])(?=.*[a-zA-Z])\w{8,}$")

3 个解决方案

#1

something like

^(?=.*[0-9])(?=.*[a-zA-Z])\w{8,}$

would work

dissected:

^ the beginning of the string

^字符串的开头

(?=.*[0-9]) look ahead and make sure that there is at least 1 digit

(?=。* [0-9])向前看并确保至少有1位数字

(?=.*[a-zA-Z]) look ahead and make sure there is at least 1 letter

(?=。* [a-zA-Z])向前看并确保至少有一个字母

\w{8,} actually match the 8+ characters

\ w {8,}实际匹配8个以上的字符

$ the end of the string

$字符串的结尾

Edit: if you want extra characters (that don't count for the 1 letter requirement) use

编辑:如果你想要额外的字符(不计入1个字母的要求)使用

^(?=.*[0-9])(?=.*[a-zA-Z]).{8,}$

this will allow for any character besides newline to be used

这将允许使用除换行符之外的任何字符

If you only want certain characters allowed, replace \w in the first regex with [A-Za-z0-9@#$%^&*] with your choice of symbols

如果您只想要允许某些字符,请将第一个正则表达式中的\ w替换为[A-Za-z0-9 @#$%^&*],并选择符号

~~^(?![0-9] $)(?![a-zA-Z_]$)\w{8,}$~~

#2

You really need an expression with three regexes :)

你真的需要一个带有三个正则表达式的表达式:)

 /\w{8}/

gives minimum 8 A-Z, a-z, 0-9 and _ chars

给出最小的8个A-Z,a-z,0-9和_个字符

/\d/

finds a single digit

找到一个数字

/[A-Za-z]/

finds a single letter.

找到一个字母。

So, in Perl:

所以,在Perl中:

$string =~ /\w{8}/ and $string =~ /\d/ and $string =~ /[A-Za-z]/

#3

Try this regular expression with positive look-ahead assertion:

尝试使用正向前瞻断言的正则表达式:

(?=[a-zA-Z]*[0-9])(?=[0-9]*[a-zA-Z])^[0-9a-zA-Z]{8,}$

The parts are:

部分是:

(?=[a-zA-Z]*[0-9]) checks for at least one character of 0-9

(?= [a-zA-Z] * [0-9])检查至少一个0-9的字符

(?=[0-9]*[a-zA-Z]) checks for at least one character of the set a-z, A-Z

(?= [0-9] * [a-zA-Z])检查集合a-z,A-Z中的至少一个字符

^[0-9a-zA-Z]{8,}$ checks for the length of at least 8 occurrences of 0-9, a-z, A-Z.

^ [0-9a-zA-Z] {8,}} $检查至少8次出现的0-9,a-z,A-Z的长度。

Or with just the basic syntax:

或者只使用基本语法:

^([0-9][a-zA-Z][0-9a-zA-Z]{6,}|[0-9]{2}[a-zA-Z][0-9a-zA-Z]{5,}|[0-9]{3}[a-zA-Z][0-9a-zA-Z]{4,}|[0-9]{4}[a-zA-Z][0-9a-zA-Z]{3,}|[0-9]{5}[a-zA-Z][0-9a-zA-Z]{2,}|[0-9]{6}[a-zA-Z][0-9a-zA-Z]+|[0-9]{7}[a-zA-Z][0-9a-zA-Z]*|[a-zA-Z][0-9][0-9a-zA-Z]{6,}|[a-zA-Z]{2}[0-9][0-9a-zA-Z]{5,}|[a-zA-Z]{3}[0-9][0-9a-zA-Z]{4,}|[a-zA-Z]{4}[0-9][0-9a-zA-Z]{3,}|[a-zA-Z]{5}[0-9][0-9a-zA-Z]{2,}|[a-zA-Z]{6}[0-9][0-9a-zA-Z]+|[a-zA-Z]{7}[0-9][0-9a-zA-Z]*)$

#1