I have a list of tuples like:
我有一个元组列表，比如:
a = [(1,2,3), (4,5)] // np.shape = (2,)
And i want to covert it into an array like structure, but of fixed shape, ie
我想把它转换成一个像结构一样的数组，但它的形状是固定的。
a = [(1,2,3), (4,5,0)] // np.shape = (2,3)
2 个解决方案
#1
3
In [69]: maxlen=max(len(i) for i in a) #get the max length of all tuples
In [70]: [i+(0,)*(maxlen-len(i)) for i in a] #fill each tuple with extra zeros
Out[70]: [(1, 2, 3), (4, 5, 0)]
#2
2
Functional way to do this would be
函数的方法是。
a = [(1,2,3), (4,5), (6, 7, 8, 9)]
from itertools import izip_longest
print zip(*izip_longest(*a, fillvalue = 0))
# [(1, 2, 3, 0), (4, 5, 0, 0), (6, 7, 8, 9)]
#1
3
In [69]: maxlen=max(len(i) for i in a) #get the max length of all tuples
In [70]: [i+(0,)*(maxlen-len(i)) for i in a] #fill each tuple with extra zeros
Out[70]: [(1, 2, 3), (4, 5, 0)]
#2
2
Functional way to do this would be
函数的方法是。
a = [(1,2,3), (4,5), (6, 7, 8, 9)]
from itertools import izip_longest
print zip(*izip_longest(*a, fillvalue = 0))
# [(1, 2, 3, 0), (4, 5, 0, 0), (6, 7, 8, 9)]