帮助regexp从括号内提取值

I would like to get a regexp that will extract out the following. I have a regexp to validate it (I pieced it together, so it may not be the the best or most efficient).

我想获得一个将提取以下内容的正则表达式。我有一个正则表达式来验证它(我把它拼凑在一起,所以它可能不是最好的或最有效的)。

some.text_here:[12,34],[56,78]

The portion before the colon can include a period or underline. The bracketed numbers after the colon are coordinates [x1,y1],[x2,y2]... I only need the numbers from here.

结肠前部分可包括周期或下划线。冒号后括号内的数字是坐标[x1,y1],[x2,y2] ......我只需要这里的数字。

And here is the regexp validator I was using (for javascript):

这是我正在使用的regexp验证器(用于javascript):

^[\w\d\-\_\.]*:(\[\d+,\d+],\[\d+,\d+])

I'm fairly new to regexp but I can't figure out how to extract the values so I can get

我对regexp相当新,但我无法弄清楚如何提取值,以便我可以得到

name = "some.text_here"
x1 = 12
y1 = 34
x2 = 56
y2 = 78

Thanks for any help!

谢谢你的帮助!

3 个解决方案

#1

Try this regular expression:

试试这个正则表达式:

/^([\w\d-_.]*):\[(\d+),(\d+)],\[(\d+),(\d+)]/

var str = "some.text_here:[12,34],[56,78]";
var match = str.match(/^([\w\d-_.]*):\[(\d+),(\d+)],\[(\d+),(\d+)]/);
alert("name = " + match[1] + "\n" + 
      "x1 = " + match[2] + "\n" +
      "x2 = " + match[3] + "\n" +
      "y1 = " + match[4] + "\n" +
      "y2 = " + match[5]);

#2

You can use the match method of string:

您可以使用string的匹配方法:

var input = "some.text_here:[12,34],[56,78]";

var matches = input.match(/(.*):\[(\d+),(\d+)\],\[(\d+),(\d+)\]/);

var output = {
  name: matches[1],
  x1: matches[2],
  y1: matches[3],
  x2: matches[4],
  y2: matches[5]
}

// Object name=some.text_here x1=12 y1=34 x2=56 y2=78

#3

You want something like:

你想要的东西:

/^(\S+):\[(\d+),(\d+)\],\[(\d+),(\d+)\]/

I am not sure if JavaScript supports the naming of caputre groups, but if it did, you could add those in as well.

我不确定JavaScript是否支持caputre组的命名,但如果确实如此,你也可以添加它们。

#1