[A-z0-9]+ regexp匹配方括号[复制]

This question already has an answer here:

这个问题已经有了答案:

• Difference between regex [A-z] and [a-zA-Z] 6 answers
• regex [A-z]和[a-zA-Z] 6答案的区别。

I'm struggling with the following regexp

我正在和下面的regexp斗争。

[A-z0-9]+

If tested against this string:

如果对该字符串进行测试:

||a919238[.--a]asd|

it returns a919238[, including the square bracket.. I tried to input my test case on regex101 to understand what's wrong, but the site regex explanation is not helping, probably I'm not able to see my mistake.

它返回a919238[，包括方括号。我试着在regex101上输入我的测试用例来理解什么是错误的，但是网站regex解释没有帮助，很可能我不能看到我的错误。

Why is the square bracket included in the result?

为什么结果中包含方括号?

3 个解决方案

#1

Because

因为

[A-z0-9]+ 
 ↑ ↑ 

is from A to z, see the ASCII table, ] appears between the two characters:

从A到z，看ASCII表，]出现在两个字符之间:

#2

A===>64
z===>122
[===>91

So it is in between the range you have defined.Use [A-Za-z0-9]+

它在你定义的范围之间。使用[A-Za-z0-9]+

#3

You can use /[a-z0-9]+/i (the i makes it case-insensitive), or /[A-Za-z0-9]+/.

您可以使用/[a-z0-9]+/i(我使它不区分大小写)，或/[A-Za-z0-9]+/。