I'm trying to write a regex to extract the value of a particular parameter from an array of content in a modx database. the format of the tags is:
我正在尝试编写一个正则表达式,以从modx数据库中的内容数组中提取特定参数的值。标签的格式是:
[[!video? &path=`_path_to_video` &width=`123` &height=`123` &someotherparm=`bar`]]
I am trying to get the content of the &path parameter using this regex:
我试图使用此正则表达式获取&path参数的内容:
preg_match_all('/\[\[path=`(.*?)`\]\]/', $content, $tags, PREG_PATTERN_ORDER) ;
but without luck - it just returns empty arrays when I dump the $tags variable.
但没有运气 - 当我转储$ tags变量时它只返回空数组。
something wrong with my regex?
我的正则表达式出了什么问题?
2 个解决方案
#1
1
Your pattern doesn't match the tag format:
您的模式与标记格式不匹配:
preg_match_all('/&path=`([^`]+)`/', $content, $tags, PREG_PATTERN_ORDER);
- Match
&path=then backtick, then - Match anything that is not a backtick up until another backtick and capture it
匹配&路径=然后反击,然后
匹配任何不是反击的东西,直到另一个反击并捕获它
If you really need to match the existence of [[ and closing ]] then:
如果你真的需要匹配[[和结束]]的存在,那么:
preg_match_all('/\[\[.*&path=`([^`]+)`.*\]\]/', $content, $tags, PREG_PATTERN_ORDER);
#2
1
Try this regex:
试试这个正则表达式:
'/\[\[.*?&path=`([^`]+?)`.*?\]\]/'
#1
1
Your pattern doesn't match the tag format:
您的模式与标记格式不匹配:
preg_match_all('/&path=`([^`]+)`/', $content, $tags, PREG_PATTERN_ORDER);
- Match
&path=then backtick, then - Match anything that is not a backtick up until another backtick and capture it
匹配&路径=然后反击,然后
匹配任何不是反击的东西,直到另一个反击并捕获它
If you really need to match the existence of [[ and closing ]] then:
如果你真的需要匹配[[和结束]]的存在,那么:
preg_match_all('/\[\[.*&path=`([^`]+)`.*\]\]/', $content, $tags, PREG_PATTERN_ORDER);
#2
1
Try this regex:
试试这个正则表达式:
'/\[\[.*?&path=`([^`]+?)`.*?\]\]/'