将Array转换为Hash，同时在Ruby中保留Array索引值

I have an array that has X number of values in it. The following array only has 4, but I need the code to be dynamic and not reliant on only having four array objects.

我有一个数组中有X个值的数组。以下数组只有4个，但我需要代码是动态的，而不是只依赖于有四个数组对象。

array = ["Adult", "Family", "Single", "Child"]

array = [“Adult”，“Family”，“Single”，“Child”]

I want to convert array to a hash that looks like this:

我想将数组转换为如下所示的哈希：

hash = {0 => 'Adult', 1 => 'Family', 2 => 'Single', 3 => 'Child'}

hash = {0 =>'Adult'，1 =>'Family'，2 =>'Single'，3 =>'Child'}

The hash should have as many key/value pairs as the array has objects, and the values should start at 0 and increment by 1 for each object.

散列应该具有与数组具有对象一样多的键/值对，并且值应该从0开始并且对于每个对象递增1。

4 个解决方案

#1

Using Enumerable#each_with_index:

使用Enumerable＃each_with_index：

Hash[array.each_with_index.map { |value, index| [index, value] }]
# => {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

As @hirolau commented, each_with_index.map can also be written as map.with_index.

正如@hirolau评论的那样，each_with_index.map也可以写成map.with_index。

Hash[array.map.with_index { |value, index| [index, value] }]
# => {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

UPDATE

UPDATE

Alterantive that use Hash#invert:

使用Hash #vert的Alterantive：

Hash[array.map.with_index{|*x|x}].invert
# => {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}
Hash[[*array.map.with_index]].invert
# => {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

#2

Another one:

另一个：

Hash[array.each_index.zip(array)]
#=> {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

Newer Ruby versions would allow:

较新的Ruby版本允许：

array.each_with_index.to_h.invert
#=> {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

#3

  Hash[*(0..array.size-1).to_a.zip(array)]
    => {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

#4

Try this

尝试这个

array.each_with_index.inject({}){ |hash, (val, i)| hash[i]=val; hash }
=> {0=>"Adult", 1=>"Family", 2=>"Single", 3=>"Child"}

#1